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ziro4ka [17]
3 years ago
7

what is the volume of a rectangular prism with a length of 10 inches, width of 12 inches and height of 6 inches

Mathematics
1 answer:
alexdok [17]3 years ago
7 0
The answer would be 720 because you times all sides length times width times height 
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The answer to 20 divided by 70 is
0.2857
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What is the equation for table A. What is the equation for table B.
xeze [42]

Answer:

A: y=-2/3x + 3

B: y=x-2

solution: (3,1)

Step-by-step explanation:

7 0
2 years ago
Please help!!!! please help!!!!!​
Nata [24]
[True]

Natural numbers are the positive integers (whole numbers) such as 1, 2, 3, and etc. So it is true that zero is less than every natural number.

[Hundreds]

The 8 in 30,846 is in the hundreds place because the 8 stands for 800.
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2 years ago
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<img src="https://tex.z-dn.net/?f=%5Csf%20%5Clim_%7Bx%20%5Cto%20%5Cinfty%7D%20%5Ccfrac%7B%5Csqrt%7Bx-1%7D-2x%20%7D%7Bx-7%7D" id=
BARSIC [14]
<h3>Answer:  -2</h3>

======================================================

Work Shown:

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}\left(\sqrt{x-1}-2x\right) }{ \frac{1}{x}\left(x-7\right) }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}*\sqrt{x-1}-\frac{1}{x}*2x }{ \frac{1}{x}*x-\frac{1}{x}*7 }\\\\\\

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}}*\sqrt{x-1}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}*(x-1)}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x}-\frac{1}{x^2}}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \frac{ \sqrt{0-0}-2 }{ 1-0 }\\\\\\\displaystyle L = \frac{-2}{1}\\\\\\\displaystyle L = -2\\\\\\

-------------------

Explanation:

In the second step, I multiplied top and bottom by 1/x. This divides every term by x. Doing this leaves us with various inner fractions that have the variable in the denominator. Those inner fractions approach 0 as x approaches infinity.

I'm using the rule that

\displaystyle \lim_{x\to\infty} \frac{1}{x^k} = 0\\\\\\

where k is some positive real number constant.

Using that rule will simplify the expression greatly to leave us with -2/1 or simply -2 as the answer.

In a sense, the leading terms of the numerator and denominator are -2x and x respectively. They are the largest terms for each, so to speak. As x gets larger, the influence that -2x and x have will greatly diminish the influence of the other terms.

This effectively means,

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 } = \lim_{x\to\infty} \frac{ -2x }{ x} = -2\\\\\\

I recommend making a table of values to see what's going on. Or you can graph the given function to see that it slowly approaches y = -2. Keep in mind that it won't actually reach y = -2 itself.

5 0
3 years ago
PLS HELP ITS MATH AND I DONT UNDERSTAND <br> No links pls and ty &lt;3
tankabanditka [31]
<h3>Answer:</h3>

C=52.08π

<h3>Solution:</h3>
  • Circumference of a circle:
  • C=2πr
  • where
  • π=3.14...
  • r= radius
  • In this case, r is equivalent to 26.04 ft.
  • C=2π×26.04
  • Multiply:
  • C=52.08π (in terms of pi)

Hope it helps.

Do comment if you have any query.

8 0
2 years ago
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