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NikAS [45]
3 years ago
5

Only the smartest person in their math class can help me with this difficult problem!!!

Mathematics
2 answers:
vodomira [7]3 years ago
6 0

Step-by-step explanation:

\tt{(5 {x}^{3}  - 3x + 6) - (2 {x}^{2}  - 4x + 8)}

While subtracting , the sign of each term of second expression changes & remove the parentheses.

⟶ \tt{5 {x}^{3}  - 3x + 6 - 2 {x}^{2}  + 4x - 8}

Combine like terms. Like terms are those which have the same base. Only coefficients of like terms can be added or subtracted.

⟶ \tt{5 {x}^{3}  - 3x + 4x + 6 - 8 - 2 {x}}^{2}

⟶ \tt{5 {x}^{3}  + x - 2 - 2 {x}^{2} }

In standard from , the expression should be written in such a way that the power of variables goes from highest to lowest.

\red{ \boxed{ \boxed{ \tt{Our \: final \: answer :  \boxed{ \tt{5 {x}^{3}  - 2 {x}^{2}  + x - 2}}}}}}

Hope I helped ! ♡

Have a wonderful day / night ! ツ

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

gulaghasi [49]3 years ago
4 0

Answer:

I'm the smartest person in my math class.

Step-by-step explanation:

While subtracting , the sign of each term of second expression changes & remove the parentheses.

⟶ 5x³-3x +6-2x²+4x-8

Combine like terms. Like terms are those which have the same base. Only coefficients of like terms can be added or subtracted.

⟶   5x³-3x+4x+6-8-2x²

⟶  5x³+x-2-2x²

In standard from , the expression should be written in such a way that the power of variables goes from highest to lowest.

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Gavin had 20 minutes to do a three problem quiz he spent 9 3/4 minutes on problem 1 and 3 4/5 minutes on problem 2 how much time
Solnce55 [7]

Gavin had 20 minutes to do a three-problem quiz.

He spent 9 3/4 minutes on problem 1.

He spent 3 4/5 minutes on problem 2.

How much time did he have left for problem 3?

We need to add the time spent on problem 1 and problem 2 and then subtract the sum from the total time.

20-(9\frac{3}{4}+3\frac{4}{5})

Simplify the above fraction

\begin{gathered} 20-(9\frac{3}{4}+3\frac{4}{5}) \\ 20-\lbrack(9+3)(\frac{3}{4}+\frac{4}{5})\rbrack \\ 20-\lbrack(12)(\frac{5\cdot3+4\cdot4}{20})\rbrack \\ 20-\lbrack(12)(\frac{15+16}{20})\rbrack \\ 20-\lbrack(12)(\frac{31}{20})\rbrack \\ 20-12\frac{31}{20} \\ 20-\frac{12\cdot20+31_{}}{20} \\ 20-\frac{271_{}}{20} \\ \frac{20\cdot20-1\cdot271}{20} \\ \frac{400-271}{20} \\ \frac{129}{20} \end{gathered}

Let us write the answer in mixed number

\frac{129}{20}=6\frac{9}{20}

Finally, convert the fractional part to seconds by multiplying the fractional part by 3

6\frac{9}{20}=6\frac{27}{60}

This means that there are 6 minutes and 27 seconds are left for problem 3.

6\frac{27}{60}

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Step-by-step explanation:

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Step-by-step explanation:

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