Ask question

Ask question

All categories

3 years ago

10

PLS HELP ME ASAP ON 4 and 5 PLS! THANK YOU SOO MUCH!!

1 answer:

kotykmax [81]3 years ago

8 0

4)row 1. 20 15 10 row 2. 6

You might be interested in

Please help. Thank you

Inessa [10]

Given:

$PQRS\sim TUVW$

In the given figure, PS=x, RS=35, UV=20, VW=25 and TW=15

To find:

The scale factor from PQRS to TUVW.

Solution:

We have,

$PQRS\sim TUVW$

We know that the corresponding sides of similar figures are proportional. The scale factor is the ratio of one side of image and corresponding side of preimage.

The scale factor is:

$k=\dfrac{VW}{RS}$

$k=\dfrac{25}{35}$

$k=\dfrac{5}{7}$

Therefore, the scale factor from PQRS to TUVW is $k=\dfrac{5}{7}$ .

6 0

3 years ago

Ber [7]

Answer:

Sara earned a commission of <em>$2,300.</em>

Step-by-step explanation:

To find the answer we will first<em> divide 5 by 100</em> and we get <em>0.05</em>. Now <em>multiply $46,000 by 0.05 </em>and we get <em>$2,300</em>. Therefore, <em>$2,300 is our answer.</em>

6 0

3 years ago

What’s the missing leg length

kow [346]

Answer:

15

Step-by-step explanation:

pythag theorum

6 0

3 years ago

Read 2 more answers

6. If you draw 35 lines on a piece of paper so that no two lines are parallel to each

umka2103 [35]

The point of intersection is the point where lines intersect.

<em>There will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Given

<em /> $n = 35$ <em> --- the number of lines</em>

<em /> $d = 3$ <em> --- no three lines are concurrent</em>

<em />

When no three line are concurrent, it means that no three lines meet at the same point.

<u>So, the sequence of intersection is:</u>

<em>0 intersection for 1 line</em>
<em>1 intersection for 2 lines</em>
<em>3 intersections for 3 lines</em>
<em>6 intersections for 4 lines</em>

<em />

Following the above sequence, the number of intersections for n lines is:

$n_k = \frac{n \times (n - 1)}{2}$

In this case, $n = 35.$

So, we have:

$n_k = \frac{35 \times (35 - 1)}{2}$

$n_k = \frac{35 \times 34}{2}$

$n_k = 35 \times 17$

$n_k = 595$

<em>Hence, there will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Read more about lines of intersections at:

brainly.com/question/22368617

7 0

3 years ago

Read 2 more answers

A spinner has 10 equally sized sections, 5 of which are gray and 5 of which are blue. The spinner is spun twice. What is the pro

zhenek [66]

Answer:

$P(Gray\ and\ Blue) = \frac{1}{4}$

Step-by-step explanation:

Given

$Sections = 10$

$n(Gray) = 5$

$n(Blue) = 5$

Required

Determine P(Gray and Blue)

Using probability formula;

$P(Gray\ and\ Blue) = P(Gray) * P(Blue)$

Calculating P(Gray)

$P(Gray) = \frac{n(Gray)}{Sections}$

$P(Gray) = \frac{5}{10}$

$P(Gray) = \frac{1}{2}$

Calculating P(Gray)

$P(Blue) = \frac{n(Blue)}{Sections}$

$P(Blue) = \frac{5}{10}$

$P(Blue) = \frac{1}{2}$

Substitute these values on the given formula

$P(Gray\ and\ Blue) = P(Gray) * P(Blue)$

$P(Gray\ and\ Blue) = \frac{1}{2} * \frac{1}{2}$

$P(Gray\ and\ Blue) = \frac{1}{4}$

3 0

3 years ago