Answer:
12.01 grams per mole
Explanation:
theres no sample or example so if theres grams of Carbon, convert it to moles using 12.01g/mol
Hey there!
Just say what color you think the mixture would look like if those elements were combined. Personally I don't know because I don't have context, but if it comes to it just pick a color :)
Good luck, have a good night.
The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants
Answer:
% oxygen = 47.1 %
% aluminium = 52.9 %
Explanation:
Step 1: Data given
Mass of aluminium = 2.70 grams
Mass of aluminium oxide = 5.10 grams
Step 2: The balanced equation
4Al + 3O2 →2Al2O3
Step 3: Calculate mass of oxygen
The law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products.
Mass oxygen + mass aluminium = mass aluminium oxide
Mass oxygen + 2.70 grams = 5.10 grams
Mass oxygen = 5.10 grams - 2.70 grams
Mass oxygen = 2.40 grams
Step 4: Calculate percent composition
% oxygen = (mass oxygen / mass aluminium oxide) * 100 %
% oxygen = (2.40 grams / 5.10 grams ) * 100 %
% oxygen = 47.1 %
% aluminium = (mass aluminium / mass aluminium oxide)
% aluminium = (2.70 grams / 5.10 grams ) * 100 %
% aluminium = 52.9 %
47.1 % + 52.9 % = 100 %
Answer:
CH₄
Explanation:
To determine the empirical formula of the hydrocarbon, we need to follow a series of steps.
Step 1: Determine the mass of the compound
The mass of the compound is equal to the sum of the masses of the elements that form it.
m(CxHy) = mC + mH = 7.48 g + 2.52 g = 10.00 g
Step 2: Calculate the percent by mass of each element
%C = mC / mCxHy × 100% = 7.48 g / 10.00 g × 100% = 74.8%
%H = mH / mCxHy × 100% = 2.52 g / 10.00 g × 100% = 25.2%
Step 3: Divide each percentage by the atomic mass of the element
C: 74.8/12.01 = 6.23
H: 25.2/1.01 = 24.95
Step 4: Divide both numbers by the smallest one, i.e. 6.23
C: 6.23/6.23 = 1
H: 24.95/6.23 ≈ 4
The empirical formula of the hydrocarbon is CH₄.