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Answer:
The total number of atoms when glucose and oxygen reacts stays the same when carbondioxide and water are produced.
Explanation:
Chemical reaction:
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O
We can see that the number of atoms of each element remain same on both side of reaction so law of conservation of mass is followed by this reaction. Six number of carbon atoms twelve number of hydrogen atoms and eighteen number of oxygen atoms are present on both side.
There are two types of respiration:
1. Aerobic respiration
2. Anaerobic respiration
Aerobic respiration
It is the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.
Glucose + oxygen → carbon dioxide + water + 38ATP
Anaerobic Respiration
It is the breakdown of glucose molecule in the absence of oxygen and produce small amount of energy. Alcohol or lactic acid and carbon dioxide are also produced as byproducts.
Glucose→ lactic acid/alcohol + 2ATP + carbon dioxide
This process use respiratory electron transport chain as electron acceptor instead of oxygen. It is mostly occur in prokaryotes. Its main advantage is that it produce energy (ATP) very quickly as compared to aerobic respiration.
There are a number of ways to express concentration
of a solution. This includes molarity. Molarity is expressed as the number of
moles of solute per volume of the solution. The concentration of the solution
is calculated as follows:
Molarity = 2.0 mole / L solution
<span>2.0 mole / L solution ( 0.50 Liters ) = 1 mole solute</span>
<span>The correct answer is the third option. One mole of solute needed to make 0.50 liters of 2M solution.</span>
Answer:
Lithium
Explanation:
The answer is Lithium because the Alkali metals family is in the group 1A and the element neon is in the second period. If you look at the periodic table group 1A and the second period connects at the element Lithium.
Answer:
4 monochlorination products can be formed.
Explanation:
Constitutional isomers : These are those compounds with same molecular formula but different atomic arrangement.For example: butane and 2-methly-propane.
On monochlorination of 2 methyl-butane we will have four possibilities of product which will be constitutional isomers of each other:
- 1-chloro-3-methyl butane :
- 2-chloro-3-methyl butane :
- 2-chloro-2-methyl butane
- 1-chloro-2-methyl butane
