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mixer [17]
3 years ago
10

Is y=x(x-1) a function

Mathematics
2 answers:
arsen [322]3 years ago
7 0

Answer:

Yes.

Step-by-step explanation:

y = x(x - 1) is a function.

If we draw a graph of the  expression  we get a parabola  which is shaped  like a U.

The graph passes the vertical line test for s function (that is -  any vertical line drawn through the curve passes through the curve at only one point).

Fed [463]3 years ago
4 0
Yes it is a function
Y=x(x-1)
X(x-1)
X to the 2nd power -1x
Hope that’s helps
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Answer:

Following are the answer to this question:

Step-by-step explanation:

Let, In the Bth place there are 8 values.

In point a:

There is no case, where it generally manages its next groom is = 7 and it will be arranged in the 2, that can be arranged in 2! ways. So, the total number of ways are: \to 7 \times 2= 14\\\\ \{(1,2),(2,1),(2,3),(3,2),(3,4),(4,3),(4,5),(5,4),(5,6),(6,5),(6,7),(7,8),(8,7),(7,6)\}\\\therefore required probability:

= \frac{14}{8!}\\\\= \frac{14}{8\times7 \times6 \times 5 \times  4 \times 3\times 2 \times 1 }\\\\= \frac{1}{8\times6 \times5 \times 4 \times 3}\\\\= \frac{1}{8\times6 \times5 \times 4 \times 3}\\\\=\frac{1}{2880}\\\\=0.00034

In point b:

Calculating the leftmost position:

\to \frac{7!}{8!}\\\\\to \frac{7!}{8 \times 7!}\\\\\to \frac{1}{8}\\\\\to 0.125

In point c:

This option is false because

\to P(A \cap B) \neq P(A) \times P(B)\\\\\to \frac{12}{8!} \neq \frac{14}{8!}\times \frac{1}{8}\\\\\to \frac{12}{8!} \neq \frac{7}{8!}\times \frac{1}{4}\\\\

3 0
3 years ago
F(x)=x^2 reflected over x=2
klasskru [66]

Answer:

please rate

Step-by-step explanation:

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Answer:

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6 0
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