Answer:
I hope this answer is helpful for you
Step-by-step explanation:
26.3+47.9=74.2
107.4-3.29=104.11
Answer:
∠y = 70º, ∠z = 60º, ∠w = 70º
Step-by-step explanation:
i believe the angle measures are the same for both triangles.
so ∠z = 60º, ∠x = 50º
to get ∠w, 180 - (50 + 60) = 70
∠w = 70º
∠w and ∠y would be equivalent
Answer:
B
Step-by-step explanation:
Comparing like terms on both sides
→ x²
Note that x² = ![\sqrt[3]{x^{6} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E%7B6%7D%20%7D)
→ 
Note that
= ![\sqrt[3]{y^{12} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%5E%7B12%7D%20%7D)
Also
54 → 3
Note that 54 = 3³ × 2
and
=
= 3![\sqrt[3]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%7D)
Hence
= 3x²
![\sqrt[3]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%7D)
Hence n = 3 → B
<span>Compose and decompose numbers from 11 to 19 into ten ones and some further ones, e.g., by using objects or drawings, and record each composition or decomposition by a drawing or equation (such as 18 = 10 + 8); understand that these numbers are composed of ten ones and one, two, three, four, five, six, seven, eight, or nine ones.</span>
Answer: Leanna ran 40.08 miles before she was passed by Irina.
Step-by-step explanation:
Let t represent the number of hours that Leanna ran before she was passed by Irina.
Leanna started in group E and ran at a rate of 4.8 miles per hour.
Distance = speed × time
Distance that Leanna ran in t hours is
4.8 × t = 4.8t
During the race, she was passed by Irina who ran at a rate of 5 miles per hour and started in group H, 20 minutes after Leanna started. 20 minutes = 20/60 = 1/3 hours. This mean that the number of hours that Irina ran before she passed Leanna is (t - 1/3) hours.
Distance that Irina ran would be
5(t - 1/3) = 5t - 5/3
Since they covered the same distance, then
4.8t = 5t - 5/3
5t - 4.8t = 5/3
0.2t = 1.67
t = 1.67/0.2 = 8.35 hours
Distance that Leanna ran before she was passed by Irina is
4.8t = 4.8 × 8.35 = 40.08 miles