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Anna11 [10]
3 years ago
11

A circuit contains two switches. The first switch transmits messages correctly 80 percent of the time, and the second switch tra

nsmits messages correctly 90 percent of the time. What percent of the time will the message be transmitted successfully through both switches?
Mathematics
1 answer:
Butoxors [25]3 years ago
5 0

Answer:

72%

Step-by-step explanation:

A circuit contains two switches.

The first switch transmits messages correctly 80% of the time, then the probability that the message will be transmitted successfully through the first switch is

p_1=0.8

The second switch transmits messages correctly 90% of the time, then the probability that the message will be transmitted successfully through the second switch is

p_2=0.9

The probability that the message will be transmitted successfully through both switches is

p=p_1\cdot p_2=0.8\cdot 0.9=0.72

that is exactly 72%

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Vera_Pavlovna [14]
<span>3√96 * √98 = </span><span>12√6 * 7√2 = 84</span>√12 = 168√3
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3 years ago
Compare 6.23 * 10^14 and 8.912 * 10^12
Masteriza [31]

Answer:

623,000,000,000,000 > 8,912,000,000,000

Step-by-step explanation:

8.912·10^12

The exponent is 12, making it 10 to the power of 12. As the exponent is positive, the solution is a number greater than the origin or base number. To find our answer, we move the decimal to the right 12 time(s):

8.912 -> 8,912,000,000,000

6.23·10^14

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3 years ago
Show with work please.
kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that \text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$

Solving the difference of sin:

$-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)$

-\cos \left(\theta\right) \cdot 1+0\cdot \sin \left(\theta\right)

-\text{cos} \left(\theta\right)

Then,

$\csc \left(\theta-\frac{\pi }{2}\right)=-\frac{1}{\cos \left(\theta\right)}$

Once

\text{sec}(-\theta)=\text{sec}(\theta)

And, \text{sec}(\theta)=-0.73

$-\frac{1}{\cos \left(\theta\right)}=-\text{sec}(\theta)$

$-\frac{1}{\cos \left(\theta\right)}=-(-0.73)$

$-\frac{1}{\cos \left(\theta\right)}=0.73$

Therefore,

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

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hammer [34]

Answer:

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But when the angle given is in degrees the length is expressed as

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