<u>Given</u>:
The coordinates of the points A, B and C are (3,4), (4,3) and (2,1)
The points are rotated 90° about the origin.
We need to determine the coordinates of the point C'.
<u>Coordinates of the point C':</u>
The general rule to rotate the point 90° about the origin is given by
Substituting the coordinates of the point C in the above formula, we get;
Therefore, the coordinates of the point C' is (-1,2)
We have to assume that the speed before being stuck was sufficient to get to the destination on time had there been no delay. Call that speed "s" in km/h.
Since 200 km is "halfway", the total distance must be 400 km.
time = distance / speed
total time = (time for first half) + (delay) + (time for second half)
400/s = 200/s + 1 + 200/(s+10) . . . .times are in hours, distances in km
200/s = 1 + 200/(s+10) . . . . . . . . . . subtract 200/s
200(s+10) = s(s+10) +200s . . . . . . .multiply by s(s+10)
0 = s² +10s - 2000 . . . . . . . . . . . . . .subtract the left side
(s+50)(s-40) = 0
Solutions are s = -50, s = 40
The speed of the bus before the traffic holdup was 40 km/h.
Answer:
∠1 = 48
∠2 = 132
∠4 - 132
Step-by-step explanation:
∠3 and ∠1 are vertical angles
vertical angles are congruent ( equal to each other )
So if ∠3 = 48° then ∠1 also = 48°
∠3 and ∠4 are supplementary angles
supplementary angles add up to equal 180°
Hence, ∠3 + ∠4 = 180
48 + ∠4 = 180
180 - 48 = 132
Hence, ∠4 = 132
∠4 and ∠2 are vertical angles
Like stated previously vertical angles are congruent
Hence, ∠2 = 132
Like terms will have exactly the same variables
so 5a and 2a are like terms
examples :
3b and 4b are like terms
3b and 4a are not like terms
2a^2 + 3a^2 are like terms
2a and 3a^2 are not like terms
3ab and 4ba are also like terms...even though the variables are switched
6b^2a and 6a^2b are not like terms
