The first number is 90, the one(second) number is 630, and the third number is 190.
<h3>Word problems leading to the algebraic equation:</h3>
Word problems in mathematics are words written with a mathematical approach and it requires the use of the student's understanding of various mathematical concepts to arrive at a probable solution to the word problems. Word problems are used in mathematics to solve our daily life challenges.
From the given information, given that:
- Let the first number be x
- One(second) number is 7 times the first number. Let that number be
- A third number is 100 more than the first number i.e
The sum of these three numbers is 910. i.e.
x+ y + z = 910
It implies that:
x + 7x + 100 + x 910
9x + 100 = 910
9x = 900 - 100
9x = 810
x = 90
y = 7(90) = 630
z = 100 + 90 = 190
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Answer:
if your asking if x is greater than 11 it will be false
Step-by-step explanation:
we know that
<u>case a)</u> ∠ABC
The geometric figure is not drawn in the diagram
<u>case b)</u> ∠BCE
The geometric figure is drawn in the diagram
<u>case c)</u> line segment CA
The geometric figure is drawn in the diagram
<u>case d)</u> Ray CA
The geometric figure is drawn in the diagram
<u>case e)</u> Circle C
The geometric figure is drawn in the diagram
<u>case f)</u> Ray BE
The geometric figure is not drawn in the diagram
<u>case g)</u> LIne segment AE
The geometric figure is not drawn in the diagram
see the attached figure to better understand the problem
Answer:
18000
Step-by-step explanation:
The 22000 females make up 55% of the population. So, we divide 22000 by 0.55 to get the total population.
22000 ÷ 0.55 = 40000
Now we take our total population and subtract 22000 to get the number of males in the population.
40000 - 22000 = 18000
The male population of the village is 18000.
Answer:
The correct answer would be 10ft