Since the degree of this polynomial is 5, there will be 5 possible zeros. To find the possible rational 0s, use the rational root theorem (p/q). P is the last, non x value, which here it is the four on the end. The q is the leading coefficient, which is also q. Next, find all of the factors of q and p, which since they are both 4, are ±1, ±2, and ±4. Next do all possible values of p/q, which are ±1, ±2, ±4, ±1/2, and ±1/4. These are all your possible rational zeros. complex 0s only come in pairs, so the maximum there can be is 4 complex zeros, meaning there is at least one rational, real 0. (i graphed it it is -1/2, so all others must be rational or imaginary)
Megan can buy 22 decorations
Here is my work
300-75=225
225/10=22.5
Since you can’t buy half of a decoration she can but 22.
a linear function has a infinite number of solutions because every time you multiply it by the square route the way you should and then multiply by seven your answer is all ways infinite
and its spelt brainliest
<span>2/7 x 26 = 7.42 would be the exact but you would round down to 7.</span>
In the Triangle ABD, Using Pythagoras theorem we can write
In the Triangle ACD using Pythagoras Theorem
Now in the larger Triangle ABC, we can write
Now substitute the values from the above equations we get
