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katovenus [111]
3 years ago
15

Simplify (25x^2-14xy+4)-(7x^2-9y)+(2xy+7)

Mathematics
1 answer:
givi [52]3 years ago
5 0
First distribute the negative to the second equation which would give you:

25x^2 - 14xy + 4 -7x^2 + 9y + 2xy + 7

Since addition is commutative. you can now just add like terms.

18x^2 - 12xy + 9y + 11
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Which of the following sets are subspaces of R3 ?
Ratling [72]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

for point A:

\to A={(x,y,z)|3x+8y-5z=2} \\\\\to  for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)

                                        =3(aX_l +bX_2) + 8(ay_1 + by_2) — 5(az_1+bz_2)\\\\=a(3X_l+8y_1- 5z_1)+b (3X_2+8y_2—5z_2)\\\\=2(a+b)

The set A is not part of the subspace R^3

for point B:

\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon  B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)

                                             =-4(aX_l +bX_2) -9(ay_1 + by_2) +7(az_1+bz_2)\\\\=a(-4X_l-9y_1+7z_1)+b (-4X_2-9y_2+7z_2)\\\\=0

\to a(x_1,y_1,z_1)+b(x_2, y_2, z_2) \varepsilon  B

The set B is part of the subspace R^3

for point C: \to C={(x,y,z)|x

In this, the scalar multiplication can't behold

\to for (-2,-1,2) \varepsilon  C

\to -1(-2,-1,2)= (2,1,-1) ∉ C

this inequality is not hold

The set C is not a part of the subspace R^3

for point D:

\to D={(-4,y,z)|\ y,\ z \ arbitrary \ numbers)

The scalar multiplication s is not to hold

\to for (-4, 1,2)\varepsilon  D\\\\\to  -1(-4,1,2) = (4,-1,-2) ∉ D

this is an inequality, which is not hold

The set D is not part of the subspace R^3

For point E:

\to E= {(x,0,0)}|x \ is \ arbitrary) \\\\\to for (x_1,0 ,0) ,(x_{2},0 ,0) \varepsilon E \\\\\to  a(x_1,0,0) +b(x_{2},0,0)= (ax_1+bx_2,0,0)\\

The  x_1, x_2 is the arbitrary, in which ax_1+bx_2is arbitrary  

\to a(x_1,0,0)+b(x_2,0,0) \varepsilon  E

The set E is the part of the subspace R^3

For point F:

\to F= {(-2x,-3x,-8x)}|x \ is \ arbitrary) \\\\\to for (-2x_1,-3x_1,-8x_1),(-2x_2,-3x_2,-8x_2)\varepsilon  F \\\\\to  a(-2x_1,-3x_1,-8x_1) +b(-2x_1,-3x_1,-8x_1)= (-2(ax_1+bx_2),-3(ax_1+bx_2),-8(ax_1+bx_2))

The x_1, x_2 arbitrary so, they have ax_1+bx_2 as the arbitrary \to a(-2x_1,-3x_1,-8x_1)+b(-2x_2,-3x_2,-8x_2) \varepsilon F

The set F is the subspace of R^3

5 0
3 years ago
A city doubles its size every 64 year. If the population is currently 225,000, what will the population be in 128 years?
Rudiy27

Answer:

=900000

Step-by-step explanation:

the current ppl=225000

after 64 years=225000×2=450000

in the next 64 yrs(128 yrs later)=450000×2=900000

3 0
3 years ago
Order the fractions below from least to greatest.<br> 1/2, 2/3, 1/4, 5/6
Natali [406]
1/4 , 1/2 , 2/3 , 5/6

I hope I helped you with your question
6 0
3 years ago
Read 2 more answers
7/12 - □ = 1/6<br><br><br>□ = ________​
xz_007 [3.2K]
The answer is 5/12 because 1/6 converts to 2/6 and 7/12-2/6 is equal to 5/12
4 0
2 years ago
Find the mean for the given set of data.<br><br> 18, 15, 22, 18, 25, 19, 23<br><br> 18<br> 19<br> 20
enot [183]

Answer:

20

Step-by-step explanation:

When you add them all up and divide by seven, you get 20

4 0
3 years ago
Read 2 more answers
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