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iragen [17]
11 months ago
9

Activity 2: Time is gold!​

Mathematics
2 answers:
Lemur [1.5K]11 months ago
6 0

Answer:

q1: it arrived at 11:45

q2: 8 hours and 45 minutes

q3: a: 6:59 AM b: 498 minutes

Step-by-step explanation:

q1: 10:30 + 1:15 = 11:45

q2: 0:30 +7:30 +0:45 +8 hours and 45 minutes

q3: a(8:18 + 10:41 PM = 6:59 AM) b(8x60= 480 +18= 489)

Svet_ta [14]11 months ago
3 0

Answer:

time is gold ............

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The top-selling Red and Voss tire is rated 50,000 miles, which means nothing. In fact, the distance the tires can run until they
Anvisha [2.4K]

Answer: 0.9726

Step-by-step explanation:

Let x be the random variable that represents the distance the tires can run until they wear out.

Given : The top-selling Red and Voss tire is rated 50,000 miles, which means nothing. In fact, the distance the tires can run until they wear out is a normally distributed random variable with a \mu=67,000 miles and a \sigma= 5,200 miles.

Then , the probability that a tire wears out before 60,000 miles :

P(x  [using p-value table for z]

Hence, the probability that a tire wears out before 60,000 miles= 0.9726

8 0
3 years ago
Which expression represents the sum of (2x-5y) and (x+y)?
trasher [3.6K]
(2x-5y) + (x+y)  
= (2x+x) + (-5y+y)
 = 3x + (-4y)
 = 3x-4y 
 So option A is the correct one.
4 0
3 years ago
Vhich of the following is a true statement about skew lines?
krok68 [10]

Answer:

A. Skew lines cannot lie in the same plane.

Step-by-step explanation:

(*Which)

Skew Line Definition (from Wikipedia): <em>"In three-dimensional geometry, skew lines are two lines that do not intersect and are not parallel." </em>-Wikipedia

<em>"Two lines that both lie in the same plane must either cross each other or be parallel, so skew lines can exist only in three or more dimensions."</em> -Wikipedia

Skew lines cannot lie in the same plane so A is correct and C is incorrect.

B and D are incorrect because our friend Wikipedia just said it was incorrect.

5 0
3 years ago
Regina, Phil, and Joseph each wrote expressions to represent their hourly earnings for an after-school job where h represents th
Vladimir79 [104]

Answer:

Disagree

On weeks when Joseph works extra 2/3 hours more than Phil, Phil and Joseph can earn the same amount of money

Step-by-step explanation:

The given expression for the hourly earnings of Regina, Phil and Joseph are as follows;

Regina: 6.50·h + 16

Phil: 3·(2.5·H + 5)

Joseph: 7.50·h + 10

The number of hours worked = h

The hourly earnings for Phil equated to the hourly earnings of Joseph gives;

3·(2.5·H + 5) = 7.50·h + 10

Simplifying we get;

3 × 2.5·h + 3 × 5 = 7.50·h + 10

7.5·h + 15 = 7.50·h + 10

Which gives

15 =  10 + 5 = 10 which is not correct.

Therefore, when both Phil and Joseph works the same number of hours, in the week, Phil will earn 5 units more Joseph

However, we have that, where Joseph works extra 5/7.5 or 2/3 hours more than Phil, every week, they will earn the same amount of money every week.

Therefore, it is possible for Phil and Joseph to earn the same amount of money when Joseph works extra 2/3 hours more than Phil which gives;

On weeks when Joseph works extra 2/3 hours more than Phil, Phil and Joseph can earn the same amount of money.

3 0
3 years ago
The radius of a cylinder gift box is box is 3X +1 inches the height of the gift box is twice the radius what is the surface area
Genrish500 [490]

Answer:

The surface area of the gift box is = A = \frac{1188}{7}x^{2}+ \frac{774}{7}x +\frac{132}{7}

Step-by-step explanation:

The surface area of the cylinder can be calculated using this formula:

A=2\pi rh+2\pi r^2

in this case, r is not a number, but rather an expression, which is r = 3x +1.

The height of the gift box is twice the radius, which is h = 2(3x+1)= 6x+2

To get our curved surface area, we carefully put the expressions for h and r into the equation.

A = 2 \times \frac{22}{7} \times (3x+1) \times (6x+2) + 2 \times \frac{22}{7} \times (3x+1)^{2}

A = \frac{44}{7} (3x+1) \times (6x +2) + \frac{44}{7} (9x^{2} + 6x +1)\\A =\frac{132}{7}x + \frac{44}{7} \times (6x+2)+ \frac{396}{7}x^{2}+\frac{246}{7}x +\frac{44}{7}

A = \frac{792}{7}x^{2} +\frac{264}{7}x +\frac{264}{7}x + \frac{88}{7} + \frac{396}{7}x^{2} + \frac{246}{7}x + \frac{44}{7}

A = \frac{1188}{7}x^{2}+ \frac{774}{7}x +\frac{132}{7}

The surface area of the gift box is = A = \frac{1188}{7}x^{2}+ \frac{774}{7}x +\frac{132}{7}

5 0
3 years ago
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