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3 years ago

Please help me I'm very confused!

Mathematics

1 answer:

NikAS [45]3 years ago

7 0

Answer:

1)6

2)36

Step-by-step explanation:

-$-#--#-#+#+#++#+#+#+#

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3 years ago

X/5+37= -3 what is x show work

kvv77 [185]

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5 0

3 years ago

How many natural numbers N have the property among 1,2,..........,N exactly 30% are divisible by 3?

k0ka [10]

Answer:

The answer is B. 2.

Step-by-step explanation:

We know that for N = 1 and N = 2, none of them are divisible by 3.

For N = 3, 33.33% are divisible by 3. For N = 4, 25% (which is already less than 30%), so N = 5 would also be less.

At N = 6, we're back up to 33.33%. N = 7 is already less than 30%.

At N = 9, you guessed it, 33.33%. N = 10 is 30% (3, 6, and 9). So we have one case.

Moving along, at N = 18, 33.33%. N = 20 is again 30% (3, 6, 9, 12, 15, and 18). Two cases now.

Finally, at N = 21, again 33.33%. N = 22 and N = 23 are both greater than 30%. As we continue this, for any N after 20, we will always be greater than 30%.

4 0

3 years ago

Someone help me understand how to do this

Wewaii [24]

Answer:

6.7 cm

Step-by-step explanation:

To make use of the Law of Sines for finding b, you need to know the missing angle B. Since the sum of the angles of a triangle is 180°, you can find angle B as ...

B = 180° -82° -55° = 43°

Now, you put the numbers you know into the formula given and solve for b.

sin(A)/a = sin(B)/b

sin(55°)/(8 cm) = sin(43°)/b

Cross multiplying gives ...

b·sin(55°) = (8 cm)·sin(43°)

and dividing by the coefficient of b gives you ...

b = (8 cm)·sin(43°)/sin(55°) ≈ 6.7 cm

4 0

3 years ago

Read 2 more answers

Consider the hypotheses below. Upper H 0: mu equals 50 Upper H 1: mu not equals 50 Given that x overbar equals 60, s equals 1

Neko [114]

Answer:

We conclude that $\mu\neq$ 50.

Step-by-step explanation:

We are given that x bar = 60, s = 12, n = 30, and alpha = 0.10

Also, Null Hypothesis, $H_0$ : $\mu$ = 50

Alternate Hypothesis, $H_1$ : $\mu$ $\neq$ 50

The test statistics we will use here is;

T.S. = $\frac{Xbar-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, X bar = sample mean = 60

s = sample standard deviation = 12

n = sample size = 30

So, Test statistics = $\frac{60-50}{\frac{12}{\sqrt{30} } }$ ~ $t_2_9$

= 4.564

At 10% significance level, t table gives critical value of 1.311 at 29 degree of freedom. Since our test statistics is more than the critical value as 4.564 > 1.311 so we have sufficient evidence to reject null hypothesis as our test statistics will fall in the rejection region.

P-value is given by, P( $t_2_9$ > 4.564) = less than 0.05% {using t table}

Here also, P-value is less than the significance level as 0.05% < 10% , so we will reject null hypothesis.

Therefore, we conclude that $\mu\neq$ 50.

7 0

3 years ago