An object is dropped from a very tall bridge. If it takes 29.48 s to reach the ground below, how high is the bridge?////
1 answer:
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Answer:
The “terminal speed” of the ball bearing is 5.609 m/s
Explanation:
Radius of the steel ball R = 2.40 mm
Viscosity of honey η = 6.0 Pa/s
While calculating the terminal speed in liquids where density is high the stokes law is used for viscous force and buoyant force is taken into consideration for effective weight of the object. So the expression for terminal speed (Vt)
Substitute the given values to find "terminal speed"
The “terminal speed” of the ball bearing is 5.609 m/s
Answer:
The resistance in first case is 12 Ω, power delivered is 12 W, and potential difference is 0.01 V
Explanation:
Given:
(A)
Current A
Voltage V
For finding the resistance,
12Ω
(B)
For finding power delivered,
Watt
(C)
For finding the potential difference,
V
Therefore, the resistance in first case is 12 Ω, power delivered is 12 W, and potential difference is 0.01 V
Answer:
300 m
Explanation:
The train accelerate from the rest so u = 0 m/sec
Final speed that is v = 80 m/sec
Time t = 30 sec
The distance traveled by first plane = 1200 m
We know the equation of motion where s is distance a is acceleration and u is initial velocity
Using this equation for first plane
As the acceleration is same for both the plane so a for second plane will be 2.67
The another equation of motion is using this equation for second plane
s = 300 m