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serg [7]
3 years ago
8

One strategy in a snowball fight is to throw

Physics
1 answer:
blondinia [14]3 years ago
7 0

Answer:

Range formula:  R = v^2 sin (2 theta) / g

If theta = 69 deg and v = 15.1

R = 15.1^2 sin 138 / 9,8 = 15.6 m

sin 138 = .669 = sin 42

So a snowball thrown at 21 deg will travel

R = 15.1 * .669^2 / 9.8 = 15.6 m

The second snowball can be thrown at 21 deg to travel the same distance

Vx = V cos theta = 15.1 * cos 69 = 5.41     first snowball

t1 = 15.6 / 5.41 = 2.88 sec

Vx = V cos theta = 15.1 cos 21 = 14.1 m/s

t2 = 15.6 / 14.1 = 1.11 sec

Difference = t1 - t2 = 1.77 sec     time delay for second snowball

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The amount of movement of the particles depends on the amount of _________ acting on them and their relationship to other atoms.
Liula [17]

Answer: The amount of movement of the particles depends on the amount of <u>force</u> acting on them and their relationship to other atoms.

Explanation:

The inter-atomic force determines the inter-atomic distance which governs the amount of movement of the particles.

For example in solids, the inter-atomic force is stronger and hence, the distance between any atoms is very very small which restricts the movement of the particles. On the other hand, in case of liquids and gases, the inter-atomic forces are not very strong and there is more distance between the atoms which allows free movement of particles.

4 0
4 years ago
A car leaves an intersection traveling west. Its position 4 sec later is 21 ft from the intersection. At the same time, another
Alex_Xolod [135]

Answer:

15.8 ft/s

Explanation:

\frac{da}{dt} = Velocity of car A = 9 ft/s

a = Distance car A travels = 21 ft

\frac{db}{dt} = Velocity of car B = 13 ft/s

b = Distance car B travels = ft

c = Distance between A and B after 4 seconds = √(a²+b²) = √(21²+28²) = √1225 ft

From Pythagoras theorem

a²+b² = c²

Now, differentiating with respect to time

2a\frac{da}{dt}+2b\frac{db}{dt}=2c\frac{dc}{dt}\\\Rightarrow a\frac{da}{dt}+b\frac{db}{dt}=c\frac{dc}{dt}\\\Rightarrow \frac{dc}{dt}=\frac{a\frac{da}{dt}+b\frac{db}{dt}}{c}\\\Rightarrow \frac{dc}{dt}=\frac{21\times 9+28\times 13}{\sqrt{1225}}\\\Rightarrow \frac{dc}{dt}=15.8\ ft/s

∴ Rate at which distance between the cars is increasing three hours later is 15.8 ft/s

6 0
4 years ago
The types of waves that transmit cell phone messages are most likely _____ . Choices: radio waves.. . gamma rays.. . ultraviolet
Anastaziya [24]
<span>Radio waves are the type of wave that most likely transmit cell phones messages. Radio waves can be used to transmit data and information at various frequencies. Gamma rays are high frequency and are dangerous to our health. Ultraviolet rays come from the sun. Infrared waves are ones we experience every day, even though it is invisible to the naked eye. This is the heat we feel from the sun. </span>
3 0
3 years ago
Read 2 more answers
Which of these is a landform created due to erosion by glaciers? Delta Horn Sandbars Spit
Marina CMI [18]

Answer:

The answer is option B, horn.

Explanation:

The landform horn was formed because when glaciers erode down to form a sharp peak which is called a horn. All of the other options are false because none of those land forms are formed because of the erosion of glaciers

4 0
3 years ago
Using the force and vector explain why the car is off the road after being hit by the bus
Vilka [71]

Answer:

Solution

Explanation:

Solution:-

- The direction of motion of bus and car can be denoted by velocity vectors ( v1 and v2 ) respectively.

- On a page draw the velocity vector v1 vertically up denoting the direction of motion of bus from origin

- Similarly,draw the velocity vector v1 horizontally left denoting the direction of motion of car from origin.

-  The force exerted by the car-bus interaction is always in the direction of motion.

- The force exerted by the bus is parallel to velocity vector as F1 and force exerted by the car is parallel to velocity vector as F2.

- The vector addition of of the two forces ( F1 and F2 ) will tell us the direction and magnitude of resultant force due to car-bus interaction.

- The resultant force will cause the car to be pushed off the road in the direction shown in the diagram.

7 0
3 years ago
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