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Aliun [14]
4 years ago
13

Need help with the last question EASY 15 Points

Mathematics
2 answers:
azamat4 years ago
4 0

Where is the last question? There is no attachment

bearhunter [10]4 years ago
4 0

Answer:

What is the question?

Step-by-step explanation:

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What is the missing number in this pattern
Alchen [17]

Answer:

16 is the missing number

Step-by-step explanation:

5 0
2 years ago
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*The sum of two numbers is 400. If the first number is decreased by 20% and the second number is decreased by 15%, then the sum
Dahasolnce [82]

Answer:

The two numbers are .8*160=128 and .85*240=204

Step-by-step explanation:

First sentence:                 x+y=400

Second sentence           .8x+.85y=400-68

Solve y in the first sentence:  y=400-x

Plug first into second:     .8x+.85(400-x)=332

Distribute:                        .8x+.85(400)-.85x=332

Combine like terms:        -.05x+.85(400)=332

Simplify(multiply):              -.05x+      340=332

Subtract 340 on both sides:    -.05x       =332-340

Simplify(subtract):                     -.05x        =-8

Divide both sides by -.05:              x        =-8/-.05

Simplify (division):                           x        = 160

So y=400-x=400-160=240

8 0
3 years ago
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Ryan wants to use the Fermi process to estimate the number of basketballs that would fill a gymnasium. As part of the process, h
Westkost [7]
A basketball is the shape of a sphere.

The volume of a sphere is given by

V= \frac{4}{3} \pi r^3

Given that the diameter of the basketball is 10 in., thus the radius is 10 / 2 = 5 in.

Thus, the volume of the basketball is given by

V= \frac{4}{3} \pi(5)^3 \\  \\ = \frac{4\times125}{3} \pi=523.6\ in^3

Therefore, The best approximate of the volume of the basketball is 5\times10^2\ in^3
3 0
3 years ago
Which number is equal to 15 a)0.015 b)1.5 c)150/100 d)3/20
myrzilka [38]

Answer:

c

Step-by-step explanation:

5 0
3 years ago
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Write an integer to describe a loss of 15 yards
Nataly_w [17]
Loss implies a negative change, so the integer will be -15.
5 0
3 years ago
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