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musickatia [10]
3 years ago
9

How can you solve the equation 4−x = 2x + 3 graphically?

Mathematics
2 answers:
pychu [463]3 years ago
7 0

Answer:

x = 1/3

Step-by-step explanation:

Hello,

we can draw the two lines defined by

   y = 4 - x

   y = 2x + 3

And search for the intersection point as below

This is the point A (1/3, 11/3)

Do not hesitate if you have any question

Thanks

Dafna1 [17]3 years ago
6 0

Answer:

Step-by-step explanation:

Graph the two lines separately but on the same graph paper, and then from the completed graph read off the coordinates of the point of intersection.

y = 4 - x has a y-intercept of 4 and a slope of -1.  Plot the point (0, 4) and then draw a line with slope -1 through it.

y = 2x + 3 has a y-intercept of 3 and a slope of 2.  Plot (0, 3) and then draw a line with slope +2 through it.  

As a check, solve for x and y algebraically:

4 - x = 2x + 3 becomes 1 - x = 2x, or 3x = 1.  Then x = 1/3.

Use y = 4 - x to find the y value when x = 1/3:

y = 4 - 1/3 = 11/3

Thus, the solution is (1/3, 11/3)

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The diagonals of a quadrilateral QRST intersect at P(-1,3). QRST has vertices at Q(3,6) and R(-4,5). What must be the coordinate
erica [24]

S = (-5,0)

T = (2,1)

Step-by-step explanation:

Step 1 :

Given

Q = (3,6) and R = (-4,5). P = (-1,3)

Let S be (a,b) and T be (c,d)

The diagonals of a parallelogram bisect each other. so in order to ensure that QRST is a parallelogram, P must be the mid point of the diagonals QS and RT.

Step 2 :

P is the midpoint  of QS

So we have (3+a) ÷ 2 =  -1  and (6 + b) ÷ 2 = 3

=> 3 + a = -2    and 6 + b = 6

=> a = -5  and b =0

So S should be (-5,0)

Step 3 :

P is the midpoint  of RT

So we have (-4+c) ÷ 2 =  -1  and (5 + d) ÷ 2 = 3

=> -4+ c = -2    and 5 + d = 6

=> c = 2  and d =1

So T should be (2,1)

Step 4 :

Answer :

S = (-5,0)

T = (2,1)

6 0
3 years ago
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