Whats the area of x=9 ft, x=22ft, and z=109*

The sum of Jim's weight and Bob's weight is 180 pounds. If you subtract Jim's weight from Bob's weight, you get half of Bob's we

Furkat [3]

Answer:

120 pounds

Step-by-step explanation:

We can use systems of equations to solve this problem. Assuming j is Jim's weight and b is Bob's weight, the equations are:

j + b = 180

b - j = 1/2b

Let's get b - j = 1/2b into standard form (b, then j, then the equal sign, then the constant.)

$b - j = \frac{b}{2}\\\frac{b}{2} - j = 0$

Now we can solve using the process of elimination.

$b + j = 180\\\\\frac{b}{2} - j = 0\\\\b + \frac{b}{2} = 180\\\\b + b \cdot 2 = 180\cdot 2\\3b = 360\\b = 120$

Now we know how much Bob weighs, for fun, let's find Jim's weight by substituting into the equation.

$120 + j = 180\\j = 180-120\\j = 60$

So Bob weighs 120 pounds and Jim weight 60 pounds.

Hope this helped!

4 0

3 years ago

Read 2 more answers

The typical Michaelis-Menten equation mathematically describes the overall rate of the reaction as V (this is because biologists

andriy [413]

Answer:

Step-by-step explanation:

5 0

3 years ago

The time between telephone calls to a cable television service call center follows an exponential distribution with a mean of 1.

Ulleksa [173]

Answer:

0.52763 is the probability that the time between the next two calls will be 54 seconds or less.

0.19285 is the probability that the time between the next two calls will be greater than 118.5 seconds.

Step-by-step explanation:

We are given the following information in the question:

The time between telephone calls to a cable television service call center follows an exponential distribution with a mean of 1.2 minutes.

The distribution function can be written as:

$f(x) = \lambda e^{-\lambda x}\\\text{where lambda is the parameter}\\\\\text{Mean} = \mu = \displaystyle\frac{1}{\lambda}\\\\\Rightarrow 1.2 = \frac{1}{\lambda}\\\\\lambda = 0.84 \\f(x) = 0.84 e^{0.84 x}$

The probability for exponential distribution is given as:

$P( x \leq a) = 1 - e^{\frac{-a}{\mu}}\\\\P(a \leq x \leq b) = e^{\frac{-a}{\mu} -\frac{-b}{\mu}}$

a) P( time between the next two calls will be 54 seconds or less)

$P( x \leq 0.9)\\= 1 - e^{\frac{\frac{-54}{60}}{1.2}} = 0.52763$

0.52763 is the probability that the time between the next two calls will be 54 seconds or less.

b) P(time between the next two calls will be greater than 118.5 seconds)

$p( x > \frac{118.5}{60}) = P(x > 1.975)\\\\ = 1 - P(x \leq 1.975) \\\\= 1 -1+ e^{\frac{-1.975}{1.2}}\\\\= 0.19285$

0.19285 is the probability that the time between the next two calls will be greater than 118.5 seconds.

6 0

3 years ago

20 pts need this question asap

AlekseyPX

It's D because 140÷3.50 is 40

7 0

3 years ago

To decrease an amount by 24% what single multiplier would you use

guapka [62]

100-24=76
76%=76/100=0.76
single multiplier=0.76

5 0

3 years ago