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natta225 [31]
4 years ago
12

What is 3X +7 equals five

Mathematics
1 answer:
NNADVOKAT [17]4 years ago
5 0

3x + 7 = 5

3x = 5 - 7

3x =  - 2

x =  \frac{ - 2}{3}

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Please Help
Vinil7 [7]

Answer:

1.2

Step-by-step explanation:

You simply have to look for a point on the graph that has an x-coordinate of -6. Only one is (-6. 1.2), so 1.2 is your answer.

3 0
3 years ago
Diego is collecting dimes and nickels in a jar. He has collected $22.25 so far. The relationship between the numbers of dimes an
svet-max [94.6K]

Answer:

Correct options are:

a) ( 0 , 445 )

d) ( 118 , 209 )

e) ( 172 , 101 )

Step-by-step explanation:

A nickel is worth 5 cents $0.05

A dime is worth 10 cents = $0.10

The relationship between the numbers of dimes and nickels, and the amount of money in dollars is represented by the equation 0.10d+0.05n=22.25. Select the THREE values (d,n) that could be solutions to the equation.

a) ( 0 , 445 )

b) ( 0.50 , 435 )

c) ( 233 , 21 )

d)( 118 , 209 )

e)( 172 , 101 )

Verifying the options

a) ( 0 , 445 )

0.10d+0.05n=22.25.

= 0.10(0) + 0.05(445) = 22.25

= 22.25 = 22.25

Options a) is correct

b) ( 0.50 , 435 )

0.10d+0.05n=22.25.

= 0.10(0.50) + 0.05(435) = 22.25

= 21.8 ≠ 22.25

Option b is incorrect

c) ( 233 , 21 )

0.10d+0.05n=22.25.

= 0.10(233) + 0.05(21) = 22.25

= 24.35 ≠22.25

Option c is incorrect

d) ( 118 , 209 )

0.10d+0.05n=22.25.

= 0.10(118) + 0.05(209) = 22.25

= 22.25 = 22.25

Option d) is correct

e) ( 172 , 101 )

0.10d+0.05n=22.25.

= 0.10(172) + 0.05(101) = 22.25

= 22.25 = 22.25

Option e) is correct

5 0
4 years ago
1. What does this quote mean to you?
garik1379 [7]

Answer:

In my opinion, the holding pen (writing or solving something) and being at war related to 3 phases.

Phase 0: Be serious with your pen, with your work.

Phase 1 : After making decision, start to draft carefully, you should list down everything which could happen, prepare well.

Phase 2: Enter the process, enter the battle, keep calm and be decisive.

< Make it quick, I guess this would be deleted as soon>

6 0
4 years ago
Read 2 more answers
Which rules of exponents will be used to evaluate the expression. Check all that apply
julia-pushkina [17]

Hello!

The answer are:

- Product of powers.

- Power of a power.

- Negative exponents.

<h2>Why?</h2>

Let's solve it!

It's a math rule that we must solve first what's into a brake or parenthesis, so,

First: Product of powers [(7)^{5}*(7)^{3}]

According to the exponent's law, we have a product of powers case, so, we need to sum the exponents and keep the base

Exponents: 5 and 3

Base: 7

Applying it we have:

(7)^{5+3}

(7)^{8}

Then,

We have a power of a power case, which involves multiplying the exponents:

[(7)^{5}*(7)^{3}]^{-4}

Exponents: 3 and -4

Then,

(7)^{8*-4}

Finally, we can apply the negative exponents, the negative exponent's rules state that negative exponents are the reciprocal of the positive exponents,

So, we will have that:

(7)^{-32}=\frac{1}{7^{32} }

Have a nice day!

6 0
3 years ago
Read 2 more answers
Ben, Cam, and Justin are lumberjacks. The number of trees they chop down is given by b + 2 c + 3 j b+2c+3jb, plus, 2, c, plus, 3
ladessa [460]

Consider the complete question is "Ben, Cam, and Justin are lumberjacks. The number of trees they chop down is given by b+2c+3j, where b is the number of hours Ben spends chopping, c is the number of hours Cam spends chopping, and j is the number of hours Justin spends chopping. How many trees do they chop down after Ben spends 8 hours chopping, Cam spends 3 hours chopping, and Justin spends 4 hours chopping?"

Given:

Total number of trees chopped by them = b+2c+3j

b = number of hours Ben spends chopping = 8

c = number of hours Cam spends chopping = 3

j = number of hours Justin spends chopping = 4

To find:

The numerical value of total number of trees chopped by them.

Solution:

Total number of trees chopped by them = b+2c+3j

Put b=8, c=3 and j=4 in the given expression.

Total=8+2(3)+3(4)

Total=8+6+12

Total=26

Therefore, total number of trees chopped by them is 26.

8 0
4 years ago
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