A circular fountain 10 feet in diameter has a circular walk 3 feet wide paved around it. What is the area of the walk?
1 answer:
Hi there!
• Radius =
ft = 5 ft.
Area of the fountain = πr² = 3.14 x (5)² = 78.5 ft²
•Radius for fountain n' walk =
= 
= 6.5 ft
Area of fountain n' walk = πr² = 3.14 x (6.5)² = 132. 6 ft²
| Area of th' Circular walk |
132.6 - 78.5 ft² = 54. 1 ft²
ar( Larger circle ) - ar( Smaller circle )
Hence,
The area of the walk around the fountain is 54. 1 ft²
~ Hope it helps!
• Radius =
Area of the fountain = πr² = 3.14 x (5)² = 78.5 ft²
•Radius for fountain n' walk =
Area of fountain n' walk = πr² = 3.14 x (6.5)² = 132. 6 ft²
| Area of th' Circular walk |
132.6 - 78.5 ft² = 54. 1 ft²
ar( Larger circle ) - ar( Smaller circle )
Hence,
The area of the walk around the fountain is 54. 1 ft²
~ Hope it helps!
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Answer:
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Step-by-step explanation:
Given as for trigonometric function :
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So, Hypotenuse² = perpendicular² + base²
or, Hypotenuse² = ( )² + (
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Or, Hypotenuse² = 3 + 8 = 11
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or, SecФ = =
<u>Second Method</u>
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Or, Sec²Ф = 1 + tan²Ф
or, Sec²Ф = 1 +
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Or, SecФ =
Hence The value of SecФ is . Answer