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Doss [256]
3 years ago
8

An architect is making a floor plan for a rectangular gymnasium.The distance between opposite corners of the gym will be 30 mete

rs and the width will be 18 meters. What will be the length of the gym?
Mathematics
2 answers:
blondinia [14]3 years ago
6 0
30^2=A^2+18^2
900=A^2+324
900-324=A^2
576=A^2
24=A
Length is 24 meters
Dafna1 [17]3 years ago
4 0

The length is: 24 meters


Here's why

So the hypotenuse theory or aka A^2 + B^2 = C^2 lets us know this:

A = 18

B = What we are looking for

C = 30


So before we apply these we're going to do some magic:

B = sqrt(-A^2 + C^2)

Now just put in the numbers

B = sqrt(-18^2 + 30^2)

B = sqrt(576)

B = 24 meters


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200 kg of brass is melted down and cast into ornamental frogs, each weight 3/20kg. How many frogs are made?
Savatey [412]

Answer:

1,333 frogs

Step-by-step explanation:

okay so we know that mass remains conserved no matter where you are.

same here ^^

if the total mass of brass is 200 kg

the total mass of the new frogs formed from it when put together will be the same :)

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5 0
3 years ago
2 Construct a rational function that will help solve the problem. Then, use a calculator to answer the question.
vaieri [72.5K]

Answer:

<u><em>Dimension of box:-</em></u>

Side of square base = 10 in

Height of box = 5 in

Minimum Surface area, S = 300 in²

Step-by-step explanation:

An open box with a square base is to have a volume of 500 cubic inches.

Let side of the base be x and height of the box is y

Volume of box = area of base × height

                 500=x^2y

Therefore, y=\dfrac{500}{x^2}

It is open box. The surface area of box, S .

S=x^2+4xy

Put  y=\dfrac{500}{x^2}

S(x)=x^2+\dfrac{2000}{x}

This would be rational function of surface area.

For maximum/minimum to differentiate S(x)

S'(x)=2x-\dfrac{2000}{x^2}

For critical point, S'(x)=0

2x-\dfrac{2000}{x^2}=0

x^3=1000

x=10

Put x = 10 into y=\dfrac{500}{x^2}

y = 5

Double derivative of S(x)

S''(x)=2+\dfrac{4000}{x^3} at x = 10

S''(10) > 0

Therefore, Surface is minimum at x = 10 inches

Minimum Surface area, S = 300 in²

7 0
3 years ago
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