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3 years ago

10

I am so lost. Please help.

1 answer:

Dvinal [7]3 years ago

5 0

Answer:

18

Step-by-step explanation:

Please see attached picture for full solution.

tanθ= opp/ adj

cosθ= adj/hyp

sinθ= opp/hyp

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The area of a circle is 52 m2. which is the circumference of the circle

xeze [42]

Area is pi x radius^2

if we divide by pi, we get 16.55211408.

If we square that number, we get 4.068428945. This number is the radius.

Circumference is diameter x pi or 2 x raidius x pi

So multiply that number by 2 and pi and we get 25.56269297 as the circumference.

3 0

3 years ago

Pls help me! and no files and pls actually help me

crimeas [40]

Answer:

To find m ( slope) we'll use the Slope Formula:

$\boxed{\sf{Slope\:(m)}=\cfrac{y_2-y_1}{x_2-x_1}}$

<u>Subtract the numbers:-</u>

$\sf 7. \:m=\cfrac{4-2}{6-5} =\boxed{2}$

_______________

$\sf 8.\: m=\cfrac{-1-3}{2-6} =\boxed{1}$

_______________

$\sf 9.\: m=\cfrac{-4-(-2)}{3-1} =\boxed{-1}$

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$\sf 10.\: m=\cfrac{0-3}{0-(-3)} =\boxed{-1}$

_______________

$\sf 11.\:m=\cfrac{4-2}{3-1} =\boxed{1}$

_______________

$\sf 12.\: m=\cfrac{1-7}{2-5} =\boxed{2}$

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$\sf 13.\:m=\cfrac{11-9}{1-(-4)} =\boxed{\frac{2}{5}}$

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$\sf 14.\:m=\cfrac{2-3}{3-5} =\boxed{\frac{1}{2}}$

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$\sf 15.\: m=\cfrac{11-5}{2-9} =\boxed{-\frac{6}{7}}$

_______________

$\sf 16.\: m=\cfrac{-7-\left(-6\right)}{8-13}=\boxed{\frac{1}{5}}$

_______________

$\sf 17.\: m=\cfrac{4-4}{6-1} =\boxed{0}$

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$\sf 18. \: m=\cfrac{2-(-7)}{5-5}=$

↑ Undefined

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6 0

3 years ago

Write and solve a real-world problem that represents the following one-variable inequality. Then solve the inequality, showing a

Ket [755]

Put x by itself
300 ≤ 3.25x
x= 92 and 1/13

5 0

3 years ago

Barry is building a fence around rround his bacyard. The backyard is in the shape of a rectangle and the longest side of the yar

STatiana [176]

Answer:

10m

Step-by-step explanation:

Recall that the perimeter of a rectangle

= (2 x Long Side) + (2 x Short Side)

we are given that each of the long side = 20m and the perimeter is 60m

substituting these into the equation,

60 = (2 x 20) + (2 x Short Side)

60 = 40 + (2 x Short Side) (subtract 40 from both sides)

60-40 = (2 x Short Side)

(2 x Short Side) = 20 (divide both sides by 2)

Short Side = 20 / 2 = 10m

3 0

3 years ago

Read 2 more answers

If f(2) = 13 and f '(x) ≥ 2 for 2 ≤ x ≤ 7, how small can f(7) possibly be?

timofeeve [1]

Answer:

23

Step-by-step explanation:

We are given that

f(2)=13

$f'(x)\geq 2$

$2\leq x\leq 7$

We have to find the possible small value of f(7).

We know that

$f'(x)=\frac{f(b)-f(a)}{b-a}$

Using the formula

$f'(x)=\frac{f(7)-f(2)}{7-2}$

$f'(x)=\frac{f(7)-13}{5}$

We have

$f'(x)\geq 2$

$\frac{f(7)-13}{5}\geq 2$

$f(7)-13\geq 2\times 5$

$f(7)-13\geq 10$

$f(7)\geq 10+13$

$f(7)\geq 23$

The small value of f(7) can be 23.

3 0

3 years ago