Draw a diagram to illustrate the problem as shown in the figure below.
The minimum depth of 2.5 m occurs at 12:00 am and at 12:30 pm.
Therefore the period i0s T= 12.5 hours.
The maximum depth of 5.5 m occurs at 6:15 am and at 6:45 pm. Therefore the period of T = 12.5 hours is confirmed.
The double amplitude is 5.5 - 2.5 = 3 m, therefore the amplitude is a = 1.5 m.
The mean depth is k = (2.5 + 5.5)/2 = 4.0 m
The model for tide depth is

That is,
d = -1.5 cos(0.5027t) + 4
where
d = depth, m
t = time, hours
A plot of the function confirms that the model is correct.
If i am correct, these values should add to 360, so I do it by
140 + 110 + 62 = 312
360 - 312 = 48
So the value of the last side must equal 48.
Your answer would be x = -9. Proof:
If 9 is filled in, you would have
(3 - 5(-9))
(3 - (-45))
48
Then
48 + 140 + 110 + 62 = 360!
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Answer:
![\sqrt[4]{x^5}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E5%7D)
Step-by-step explanation:
A fraction exponent converts into a radical. The denominator is the index of the radical (farthest left number) and the numerator is the exponent of the base inside (the farthest right number). The base of the fraction exponent is the base number in green. To write this expression, simply the exponents into one exponent and one base.

Now convert to the radical.
![x^{\frac{5}{4}} = \sqrt[4]{x^5}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7B5%7D%7B4%7D%7D%20%3D%20%5Csqrt%5B4%5D%7Bx%5E5%7D)
.23 and .24 is your answer.