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Semmy [17]
3 years ago
15

A yearbook printer charges based on the number of pages printed. Here is a table that shows the cost of some recent yearbooks.

Mathematics
2 answers:
inessss [21]3 years ago
6 0

Answer:

y = 0.012x + 0.65

Step-by-step explanation:

In order to confirm which equation gives the cost of y in terms of the number of pages x, each and every equation needs to be checked out.

Assuming y = 1.25 and x = 50 (as given in question)

First Equation:

y = 0.012x + 0.65

y = 0.012(50) + 0.65

y = 0.6 + 0.65

y = 1.25

Second Equation:

y = 0.012x + 1.25

y = 0.012(50) + 1.25

y = 0.6 + 1.25

y = 1.85

Third Equation:

y = 0.012x + 49.985

y = 0.012(50) + 49.985

y = 0.6 + 49.985

y = 55.985

Fourth Equation:

y = 83.3x + 0.65

y = 83.3(50) + 0.65

y = 4165 + 0.65

y = 4165.65

Hence, only the first equation is resulting in the cost y in terms of the number of pages x. Therefore, is the correct one.

Keith_Richards [23]3 years ago
4 0

Using the first X and Y value replace the values in the equation and see which one works:

1.25 = 0.012(50) + 0.65

0.012(5) = 0.6 +0.65 = 1.25

The first equation works

Now try the second set: of values to check:

1.85 = 0.012(100) +0.65

0.012*100 = 1.20 + 0.65 = 1.85

The first equation is the correct one.

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3 years ago
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Ray Of Light [21]

Step-by-step explanation:

the total cost is, of course, first the cost to buy the copier, and then the running costs per copy made.

it is really that easy.

the equations just put this into mathematical form :

A

y = 0.02×x + 800

B

y = 0.06×x + 600

please notice, we put $600 or $800 in as constant term, because these costs are the starting costs that we have, even if we never make a single copy (x = 0).

and then the total cost goes up with every copy we make.

I cannot draw here.

so, to find the number of copies where both copier systems would cost the same, means we have to say both equating deliver the same result :

0.02×x + 800 = 0.06×x + 600

200 = 0.04×x

x = 200 / 0.04 = 5000

when making 5000 copies both costs are the same.

4 0
2 years ago
What would the number 8671.42578125 ten be in IEEE 754 single precision floating point format. You need to follow the following
Arlecino [84]

Answer:

Step-by-step explanation:

Answers are explained/Solved in the attach document.

5 0
3 years ago
Please help with 11c!?
Contact [7]

Answer:

"To the nearest year, it would be about 9 years"

Step-by-step explanation:

11c)

This is compound growth problem. It goes by the formula:

F=P(1+r)^t

Where

F is the future amount

P is the present (initial) amount

r is the rate of growth, in decimal

t is the time in years

Given,

P = 20,000

r = 8% = 8/100 = 0.08

F = double of initial amount = 2 * 20,000 = 40,000

We need to find t:

F=P(1+r)^t\\40,000=20,000(1+0.08)^t\\2=(1.08)^t

To solve exponentials, we can take Natural Log (Ln) of both sides:

2=(1.08)^t\\Ln(2)=Ln((1.08)^t)

Using the rule shown below we can simplify and solve:

Ln(a^b)=bLn(a)

We can write:

Ln(2)=Ln((1.08)^t)\\Ln(2)=tLn(1.08)\\t=\frac{Ln(2)}{Ln(1.08)}\\t=9.0064

To the nearest year, that would be about 9 years

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