A wire is formed into a circle having a diameter of 10.3 cm and is placed in a uniform magnetic field of 2.98 mT. The wire carri
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Answer:
I(x) = 1444×k ×
I(y) = 1444×k ×
I(o) = 3888×k ×
Explanation:
Given data
function = x^2 + y^2 ≤ 36
function = x^2 + y^2 ≤ 6^2
to find out
the moments of inertia Ix, Iy, Io
solution
first we consider the polar coordinate (a,θ)
and polar is directly proportional to a²
so p = k × a²
so that
x = a cosθ
y = a sinθ
dA = adθda
so
I(x) = ∫y²pdA
take limit 0 to 6 for a and o to for θ
I(x) = y²p dA
I(x) = (a sinθ)²(k × a²) adθda
I(x) = k da ×
(sin²θ)dθ
I(x) = k da ×
(1-cos2θ)/2 dθ
I(x) = k ×
I(x) = k × × (
I(x) = k × ×
I(x) = 1444×k × .....................1
and we can say I(x) = I(y) by the symmetry rule
and here I(o) will be I(x) + I(y) i.e
I(o) = 2 × 1444×k ×
I(o) = 3888×k × ......................2
To solve this problem we will apply the given concept for torque which explains the relationship between the force applied and the distance to a given point. Mathematically this relationship is given as
Where,
Torque
F = Force
d = Distance
Our values are given as,
Therefore replacing we have that the force is
F = 12.72N
Therefore the least amount of force that you must exert is 12.72N