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Nezavi [6.7K]
3 years ago
13

A wire is formed into a circle having a diameter of 10.3 cm and is placed in a uniform magnetic field of 2.98 mT. The wire carri

es a current of 5.00 A. Find the maximum torque on the wire.
Physics
1 answer:
Ksju [112]3 years ago
8 0

Answer:

T(max) = 1.17 × 10⁻⁴Nm

= 117μNm

Explanation:

T = BIA sinθ

A = area enclosed

θ = angle between normal plane

for max. torque θ = 90, (sin90° =1)

T = BIA sin90°

T= BI (πd/4)

T = T_m_a_x = \frac{1}{4} (2.98 * 10^-^3)(5)(\pi )\\T_m_a_x = 1.17 * 10^-^4Nm\\T_m_a_x = 117UNm

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Newton's second law states that the resultant of the forces applied to an object is equal to the product between the object's mass and its acceleration:
\sum F = ma
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We are only concerned about what it happens on the horizontal axis, so there are two forces acting on the cart+child system: the force F of the man pushing it, and the frictional force F_f acting in the opposite direction. So Newton's second law can be rewritten as
F-F_a = ma
or
F=ma + F_f

since the frictional force is 15 N and we want to achieve an acceleration of a=1.50 m/s^2, we can substitute these values to find what is the force the man needs:
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What is the minimum v (in km/s) the rocket engines must provide to allow the craft to escape from the Earth?
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as your roller coaster climbs to the top of the steepest hill on its track when does the first car have the greatest potential e
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Explanation:

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v = at + v₀

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The rolling resistance for steel on steel is quite low; the coefficient of rolling friction is typically μr=0.002. Suppose a 180
Irina18 [472]

Answer:

t = 0.354 hours

Explanation:

given,

coefficient of rolling friction μr=0.002

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rolling speed = 25 m/s

The force of friction = μ mg

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now,

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