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mrs_skeptik [129]
3 years ago
15

Classify the following matter

Physics
1 answer:
AURORKA [14]3 years ago
7 0

Answer:

Woah

Explanation:

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Ann puts a beaker on the scale which shows the mass to be 1.65kg. The actual mass was 1.72 kg. what was the percent error in Ann
mojhsa [17]

Measured reading is 1.65 kg

actual reading was 1.72 kg

error in the reading is 1.72 - 1.65 = 0.07 kg

Now percentage error is given as

error = \frac{error}{true reading}*100

error = \frac{0.07}{1.72}*100

error = 4.1

<em>so this is -4.1% error as the measured reading is less than the actual value</em>

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Help me and get points..
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B) Depends on launch speed.

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This is true when considering the basketball player in a given basketball game. The speed at which the player jumps up is a strong factor which determines the acceleration of his acceleration. The direct co-relation show that, speed and acceleration of the basketball player are interrelated.

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Classical mechanics is an extremely well tested model. Hundreds of years worth of experiments, as well as most feats of engineer
djyliett [7]

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The Answer is 0.019998c

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7 0
3 years ago
Small particles in an atom have an ------ charge
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It has a neutral charge which means it is equal.
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Read 2 more answers
A 60-turn coil has a diameter of 13 cm. The coil is placed in a spatially uniform magnetic field of magnitude 0.60 T so that the
kramer

Answer:

a) 0.5985 V

b) 0.05985 V

c) 0.00684 V

Explanation:

Given that

Number of turn in the coil, N = 60 turns

Magnetic field of the coil, B = 0.6 T

Diameter of the coil, d = 0.13 m

If area is given as, πd²/4, then

A = π * 0.13² * 1/4

A = 0.0133 m²

The induced emf, ε = -N(dΦ*m) /dt

Note, Φm = BA

Substituting for Φ, we have

ε = -NBA/t.

Now, we substitute for numbers in the equation

ε = -(60 * 0.6 * 0.0133)/0.8

ε = 0.4788/0.8

ε = 0.5985 V

at 8s,

ε = -(60 * 0.6 * 0.0132)/8

ε = 0.4788/8

ε = 0.05985 V

at 70s

ε = -(60 * 0.6 * 0.0132)/70

ε = 0.4788/70

ε = 0.00684 V

8 0
4 years ago
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