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Leokris [45]
3 years ago
9

PLEASE HELP!!

Physics
1 answer:
BartSMP [9]3 years ago
4 0

Answer:A) 19.8 seconds

B) 467.5 metres

Explanation: 100km/hr = 27.78m/s

So, it covers 27.78 metres in one second

Take the time it would cover 550m as x

Therefore 27.78m = 1second

550m = x

Cross multiplying

27.78x = 550m

Divide both sides by the coefficient of x

x = 550÷27.78

x = 19.8seconds

B) distance = speed × time

Speed = 85km/hr = 23.61m/s

Time = 19.8seconds

Therefore,

Distance = 23.61 × 19.8

Distance = 467.5m

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Throw two balls from the same height at the same time at an initial speed of 20 m/s. One is thrown vertically down, while the ot
labwork [276]

The time difference between their landing is 2.04 seconds.

<h3>Time of difference of the two balls</h3>

The ball thrown vertical upwards will take double of the time taken by the ball thrown vertically downwards.

Time difference, = 2t - t = t

t = √(2h/g)

where;

  • h is the height of fall
  • g is acceleration due to gravity

Apply the principle of conservation of energy;

¹/₂mv² = mgh

h = v²/2g

where;

  • v is speed of the ball

h = (20²)/(2 x 9.8)

h = 20.41 m

<h3>Time of motion</h3>

t = √(2 x 20.41 / 9.8)

t = 2.04 s

Thus, the time difference between their landing is 2.04 seconds.

Learn more about time of motion here: brainly.com/question/2364404

#SPJ1

6 0
2 years ago
A 36.3 kg cart has a velocity of 3 m/s. How much kinetic energy does the object have?
uysha [10]

Answer:

163.35

__________________________________________________________

<u>We are given:</u>

Mass of the object (m) = 36.3 kg

Velocity of the object (v) = 3 m/s

<u>Kinetic Energy of the object:</u>

We know that:

Kinetic Energy = 1/2(mv²)

KE = 1/2(36.3)(3)²            [replacing the variables with the given values]

KE = 18.15 * 9

KE = 163.35 Joules

Hence, the cart has a Kinetic Energy of 163.35 Joules

7 0
3 years ago
If one 9V battery is used in a circuit with a total resistance of 39Ω, what is the current in the circuit?
Ket [755]

Answer:

Using V= IR

I= 0.2307 Ampere

6 0
3 years ago
a current of 180 mini amphere passes through a conductor for 5minute calculate the quantity of electricity transported​
oksano4ka [1.4K]

Answer:

Explanation:

You can calculate the total electric charge that passes through the conductor as q=It=(180\times 10^{-3})(5\times 60)= 54 C. It means that the number of electron that passes through the conductor is:

n=\frac{q}{e}=\frac{54}{1.6\times 10^{-19}}=33.75\times 10^{19}

8 0
2 years ago
In the woman's mouth if
Tpy6a [65]

Answer:

hi mate,

interesting question, first of all the pressure is determined by using the following formula:

Pg = p * G * h  

where p is the density of the liquid, G is the gravity and h is the height difference, in you case you have:

p = 1015 kg/m3

G = 9.8m/s2

h = 0.085 m  

insert these values into the equation above:

Pg = 1015 kg/m3 * 9.8m/s2 * 0.085 m = 849.81 kg·m-1·s-2 or 849.81 pascal

hope it helps, :-)

please mark me as brainliest

7 0
3 years ago
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