Cos 0 = 12/15. find sin 0.

Mathematics

1 answer:

valentina_108 [34]2 years ago

3 0

Answer:

$sin \theta = \frac{3}{5}$

Step-by-step explanation:

$cos \theta = \frac{12}{15}\\\\cos^2 \theta = 1 - sin^2 \theta\\\\sin^2\theta = 1 - cos^2 \theta\\\\$

$= 1 - (\frac{12}{15})^2\\\\= 1 - \frac{144}{225}\\\\= \frac{225 - 144}{225}\\\\=\frac{81}{225}$

$sin \theta = \sqrt{\frac{81}{225}} = \frac{9}{15} = \frac{3}{5}$

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