How many potential phone numbers can be created from the last seven digits (XXX – XXXX) if each digit can be any number 0-9?
1 answer:
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So it seems as if the first problem is asking this:
.
If x=0.15, then 11/15*(0.15) is 0.11 or 11/100.
The second problem is asking:
To solve algebraically, you want to get rid of the denominators under the x's. To do so, you want to multiply by the Least Common Multiple (LCM) of the denominators. For 3 and 4, the LCM is 12. Multiply everything by 12 to get:
3x+6=4x+2
Now, solve for x
Subtract 4x from both sides:
-x+6=2
Subtract 6 from both sides:
-x=-4
Multiply by -1 on both sides:
x=4.
If x=0.15, then 11/15*(0.15) is 0.11 or 11/100.
The second problem is asking:
To solve algebraically, you want to get rid of the denominators under the x's. To do so, you want to multiply by the Least Common Multiple (LCM) of the denominators. For 3 and 4, the LCM is 12. Multiply everything by 12 to get:
3x+6=4x+2
Now, solve for x
Subtract 4x from both sides:
-x+6=2
Subtract 6 from both sides:
-x=-4
Multiply by -1 on both sides:
x=4.