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2 years ago

Explanation and answer please :)

Mathematics

1 answer:

Juli2301 [7.4K]2 years ago

6 0

$20,000 is between $15,000 and $49,999, so we'll use the interest rate of 6.5% (see row 3)

r = 6.5% = 6.5/100 = 0.065

We'll use the decimal form of the interest rate as it is most common for financial math problems.

P = 20,000 is the amount deposited

t = 1 year is the amount of time

We will plug those values into the formula

i = P*r*t

to get the following:

i = P*r*t

i = 20000*0.065*1

i = 1300

So Mark earns $1,300 in simple interest each year.

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HELP ME ASAP!!!!!!!!

Marina CMI [18]

Answer:

Step-by-step explanation:

1) 30 : 100 = x : 299

x = (30 x 299)/100

x = 89,70 $

2) 299 - 89,70 = 209,30 $

3) 5 : 100 = x : 209,30

x = 10,465 $

209,30 + 10,465 = 219,77 $

5 0

2 years ago

Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed

vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 11-1 = 10$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have $T = 1.812$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{4}{\sqrt{11}} = 1.2060$

Now, we multiply T and s

$M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8$ cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

$L = 97 + 2.19 = 99.19 = 99.2$ cm

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm).

7 0

3 years ago

during the 8-month shrimping season in the Gulf mexico, 325 shrimpers caught 4,913,977 pounds of shrimp and sold the shrimp $2 p

Hatshy [7]

STEP 1:
Find the $ total sold. Multiply total pounds by $2 sale price per pound.

=4,913,977 pounds * $2 a pound
=$9,827,954 total sold

STEP 2:
Divide the total sold above by the 325 shrimpers.

=$9,827,954 ÷ 325
=$30,239.858

Rounded to nearest dollar:
Each of the 325 shrimpers will take home $30,240.

Hope this helps! :)

4 0

2 years ago

Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '[infinity]' or

soldi70 [24.7K]

Answer:

The limit of this function does not exist.

Step-by-step explanation:

$\lim_{x \to 3} f(x)$

$f(x)=\left \{ {{9-3x} \quad if \>{x \>< \>3} \atop {x^{2}-x }\quad if \>{x\ \geq \>3 }} \right.$

To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

$\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L$

and the limit does not exist if

$\lim_{x \to a^{-}} f(x) \neq \lim_{x \to a^{+}} f(x)$

Evaluate the one-sided limits.

The left-hand limit

$\lim_{x \to 3^{-} } 9-3x= \lim_{x \to 3^{-} } 9-3*3=0$

The right-hand limit

$\lim_{x \to 3^{+} } x^{2} -x= \lim_{x \to 3^{+} } 3^{2}-3 =6$

Because the limits are not the same the limit does not exist.

8 0

3 years ago

Could someone help me step by step with this question?

a_sh-v [17]

$\frac{2}{3}(9+x)=-5(4-x) \\ \\ 3*\frac{2}{3}(9+x)=3*[-5(4-x)] \\ \\ 2(9+x)=-15(4-x) \\ \\ 18+2x=-60+15x \\ \\ -13x=-78 \\ \\ \cfrac{-13x}{-13} = \cfrac{-78}{-13} \\ \\ x=6$

7 0

2 years ago