Answer:
4 units wide
Step-by-step explanation:
Let the width of the table be 'w'
Given:
Perimeter of the table is, 
The perimeter of the rectangular table is given as the sum of all the sides of the rectangle. The sides include two lengths and two widths.
Length of the table is 8 times longer than its width. Therefore,
Now, perimeter is given as:
Now, plug in 72 for 'P' and solve for 'w'. This gives,
So, the table is 4 units wide.
Answer:
Step-by-step explanation:
1. The slope-intercept form of a linear equation is 
, where y = y-coordinate, m = slope, x = x-coordinate, and b = slope.
2. To find the slope, let's take the two points (0,0) and (-40,10). After that, let's plug in the values to their corresponding variable in the formula: 
3. Since we now know our slope, the equation looks like this so far: 
.
4. Because b is the y-intercept, b = 0 because the line intersects the y-axis at (0,0).
5. Now that we have the values of m and b, we plug in them to get the equation of: 
1. Introduction. This paper discusses a special form of positive dependence.
Positive dependence may refer to two random variables that have
a positive covariance, but other definitions of positive dependence have
been proposed as well; see [24] for an overview. Random variables X =
(X1, . . . , Xd) are said to be associated if cov{f(X), g(X)} ≥ 0 for any
two non-decreasing functions f and g for which E|f(X)|, E|g(X)|, and
E|f(X)g(X)| all exist [13]. This notion has important applications in probability
theory and statistical physics; see, for example, [28, 29].
However, association may be difficult to verify in a specific context. The
celebrated FKG theorem, formulated by Fortuin, Kasteleyn, and Ginibre in
[14], introduces an alternative notion and establishes that X are associated if
∗
SF was supported in part by an NSERC Discovery Research Grant, KS by grant
#FA9550-12-1-0392 from the U.S. Air Force Office of Scientific Research (AFOSR) and
the Defense Advanced Research Projects Agency (DARPA), CU by the Austrian Science
Fund (FWF) Y 903-N35, and PZ by the European Union Seventh Framework Programme
PIOF-GA-2011-300975.
MSC 2010 subject classifications: Primary 60E15, 62H99; secondary 15B48
Keywords and phrases: Association, concentration graph, conditional Gaussian distribution,
faithfulness, graphical models, log-linear interactions, Markov property, positive
Answer: Picking the first option and constantly adding on and on you will eventually make way more than what the second option proposes, therefore picking the first option is the obvious choice.
Step-by-step explanation:
Well let’s see it starts off slow for instance 1, 2, 4, 8, 16 and so on adding that on for a month will eventually leave you with more.
1532 ÷ 36 = 42 and remain 20.
So there were 20 CDS in the remains box
