Answer:
If the expression is
, then the answer is the first option.
If the expression is
, then the answer is the third option.
Step-by-step explanation:
Remember that when you have a radical expression in the form
, you can rewrite as:

Then:
- If the expression is
, then you can rewrite it in the following radical form:
(This form matches with the first option.)
- If the expression is
, then you can rewrite it in the following radical form:
(This form matches with the third option).
Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.
Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.
An example of such system of equation is
x > 0
y > 0
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.
Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.
Substituting C(2, 2) into the system we have:
2 > 0
2 > 0
as can be seen the two inequalities above are true, hence point C is a solution to the set of inequalities.
Part C:
Given that </span><span>Natalie
can only attend a school in her designated zone and that Natalie's zone is
defined by y < −2x + 2.
To identify the schools that
Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.
For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true
For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true
For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false
For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true
For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false
For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false
Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
</span>
Answer:
$350,000
Step-by-step explanation:
Let's define:
- s: amount of short-range missiles produced
- m: amount of medium-range missiles produced
- l: amount of long-range missiles produced
From the total production and the ratios we can write the following equations:
s + m + l = 3000
s/m = 3/3 = 1 = m/s
s/l = 3/4 or l/s = 4/3
Dividing the first equation by s, we get:
s/s + m/s + l/s = 3000/s
1 + 1 + 4/3 = 3000/s
10/3 = 3000/s
s = 3000*3/10 = 900
m = 900
l = 4/3*900 = 1200
From the money that the countries plans to use and each missile cost, we can write the following equation:
200,000*s + 300,000*m + cost*l = 870,000,000
Replacing with previous result:
200,000*900 + 300,000*900 + cost*1200 = 870,000,000
cost = (870,000,000 - 200,000*900 - 300,000*900)/1200 = 350,000
Answer:
D part
Step-by-step explanation:
3x + 80⁰ + 2x = 180⁰ (By Linear Pair)
5x + 80⁰ = 180⁰
5x = 100⁰
x = 20⁰
Hope it helps :)
Answer:
A 99.96%
Step-by-step explanation:
The z score shows by how many standard deviations the raw score is above or below the mean. The z score is positive if the raw score is above the mean while the z score is negative if the raw score is below the mean. The z score is given by:

The probability can be gotten from the normal distribution table. Therefore from the normal table:
P(z < 3.37) = 0.9996 = 99.96%