Find the measures (in degrees) of the remaining angles of trapezoid ABCD (not shown) if
1 answer:
Answer: D=128 degrees, B=56 degrees
Step-by-step explanation:
It is known that sum of two angles in trapezoid which are close to the side leg ( sides that are not parallel to each other)=180 degrees. Otherwise A+D=C+B=180 degrees
So A+D=180
52+D=180
D=128 degrees
124+ B=180
B=180-124= 56 degrees
You might be interested in
Answer:
As law of sin:
CD/sinE = DE/sinC
Then
12/sin83 = 5/sinC
Then
sinC = 5*sin83/12 = 0.413
Then
C = arcsin(0.413) = ~24.4 deg
Then
D = 180-C-E = 180-83-24.4 = ~72.6
Hope this help, bro!
This will be 2400 cause there is nothing in the ones place
Answer:a
Step-by-step explanation:
1- B
-3 1/2
