24-4m=42m-24+2
24+24-2=42m+4m
46=46m
m=1
Standard form for first one is
ax+by=c
6y-12=-3x
add 3x both sides
3x+6y-12=0
add 12
3x+6y=12
second one
distribute (don't forget double negative y)
10-2x+2y=3x+1
minus 3x both sides
10-5x+2y=1
minus 10 both sides
-5x+2y=-9
the equations are
3x+6y=12
-5x+2y=-9
From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.
Using pythagoras theorem,

and

Angle θ is given by

Given that a = 4 units, b = 5 units, and c = 9 units, thus

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.

Given that x is a point on line segment AB, this means that x is a positive number less than 5.
Thus

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
The lowest term is 3
---
4
hope this helps
<span>0.888 = 888 / 1000
hope that helps</span>