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2 years ago

I need help please!!

Mathematics

1 answer:

Harrizon [31]2 years ago

3 0

I'll do 1 and 8, and you should then be able to do 2 and 9!

For 1, we can multiply these separately - 3*4*9=108 and 5+7+2=13 (exponent multiplication is adding them!), so we have 108b^13

For 8, we can again add the exponents up to get (5/7)^8

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(-2/3)^7*(3/5)^6*(5/6)^5*(1/3)^-7 simplify of law of indices

Wewaii [24]

Answer:

$\boxed {-\frac{12}{5}}$

Step-by-step explanation:

Solve the following expression:

$(-\frac{2}{3})^{7} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

-Calculate $-\frac{2}{3}$ to the power of $7$ :

$(-\frac{2}{3})^{7} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

$-\frac{128}{2187} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

-Calculate $\frac{3}{5}$ to the power of $6$ :

$-\frac{128}{2187} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

$-\frac{128}{2187} \times (\frac{729}{15625}) \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

-Multiply both $-\frac{128}{2187}$ and $\frac{729}{15625}$ :

$-\frac{128}{2187} \times (\frac{729}{15625}) \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

$-\frac{128}{46875} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

-Calculate $\frac{5}{6}$ to the power of $5$ :

$-\frac{128}{46875} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

$-\frac{128}{46875} \times (\frac{3125}{7776}) \times (\frac{1}{3})^{-7}$

-Multiply both $-\frac{128}{46875}$ and $\frac{3125}{7776}$ :

$-\frac{128}{46875} \times (\frac{3125}{7776}) \times (\frac{1}{3})^{-7}$

$-\frac{4}{3645} \times (\frac{1}{3})^{-7}$

-Calculate $\frac{1}{3}$ to the power of $-7$ :

$-\frac{4}{3645} \times (\frac{1}{3})^{-7}$

$-\frac{4}{3645} \times 2181$

-Multiply both the $-\frac{4}{3645}$ and $2187$ :

$-\frac{4}{3645} \times 2181$

$\boxed {-\frac{12}{5}}$

Therefore, the final answer is $-\frac{12}{5}$ .

3 0

2 years ago

A spinner has 5 equal sections numbered 1 to 5. What is the probability of the spinner stopping on a number that is a multiple o

Umnica [9.8K]

Answer:

0.6

Step-by-step explanation:

Given that the spinner has 5 equal sections numbered 1 to 5.

Total Sample Space, n(S)=5

Multiples of 2 in 1 to 5 are: {2,4}

Number less than than 3 are:{1,2}

Since we are required to find the probability of the spinner stopping on a number that is a multiple of 2 or is less than 3, we take the union of both sets.

{2,4} $\cup$ {1,2} ={1,2,4}

Number of Outcomes=3

Therefore,

Probability of the spinner stopping on a number that is a multiple of 2 or is less than 3 $=\dfrac{3}{5}=0.6$

5 0

2 years ago

What is a negative minus a negative

Rainbow [258]

Answer:

It would be a negative or positive depending on the situation.

Step-by-step explanation:

A negative minus a negative would result in either a positive or negative. For example, -8 - (-9) would be 1 while -8 - (-7) would be -1. If the negative number your subtracting is greater than the number you're subtracting from then it will be positive, vice versa.

3 0

2 years ago

Hi guys this is my question

sasho [114]

Answers -

statement B, D, E are correct .

Solution -

As figure B is the scaled copy of figure A, so it is smaller than B and its perimeter is also less than that of A.

On the other hand , as B is the smaller replica of A, so it has same number of edges ,angels and sides. Though the length of the sides are not same, the angels are same. so the perimeters of both figures are different but sum of all the angels are same.

5 0

3 years ago

What are the questions

kenny6666 [7]

The answers are, from 7 to 14,

11/3

50/6

49/6

18/8

11/2

7/4

26/5

14/6

3 0

2 years ago