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belka [17]
3 years ago
7

Ryan has x stamps in his collection if he was 6 times as many stamps as penny, how many stamps does penny have in her collection

in temas of x?
Mathematics
1 answer:
Free_Kalibri [48]3 years ago
7 0

The number of stamps with penny in terms of x is \frac{x}{6}

<em><u>Solution:</u></em>

Given that,

Ryan has x stamps in his collection

Number of stamps of Ryan = x stamps

Let the stamps with penny be "a"

Ryan has 6 times as many stamps as penny

Therefore,

Number of stamps in Ryan = 6 times as many stamps as penny

\text{Number of stamps in Ryan } = 6 \times a\\\\x = 6a\\\\a = \frac{x}{6}

Thus number of stamps with penny in terms of x is \frac{x}{6}

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The simplified form of R(x) is R(x) =\frac{x^{2} -13x+42}{x^{2} -10x+25}

<h3>Simplifying an expression </h3>

From the question, we are to simplify the expression

From the given information,

f(x) =\frac{x^{2}-11x+28 }{x^{2}-11x+30}

and

g(x) =\frac{x^{2}-9x+20 }{x^{2}-12x+36}

Also,

R(x) = f(x) \div g(x)

∴ R(x) =\frac{x^{2}-11x+28 }{x^{2}-11x+30} \div \frac{x^{2}-9x+20 }{x^{2}-12x+36}

R(x) =\frac{x^{2}-11x+28 }{x^{2}-11x+30} \times \frac{x^{2}-12x+36 }{x^{2}-9x+20}

Factoring each of the quadratics

R(x) =\frac{x^{2}-7x-4x+28 }{x^{2}-6x-5x+30} \times \frac{x^{2}-6x-6x+36 }{x^{2}-4x-5x+20}

R(x) =\frac{x(x-7)-4(x-7) }{x(x-6)-5(x-6)} \times \frac{x(x-6)-6(x-6) }{x(x-4)-5(x-4)}

R(x) =\frac{(x-4)(x-7)}{(x-5)(x-6)} \times \frac{(x-6)(x-6)}{(x-5)(x-4)}

Simplifying

R(x) =\frac{(x-7)}{(x-5)} \times \frac{(x-6)}{(x-5)}

R(x) =\frac{(x-7)(x-6)}{(x-5)(x-5)}

R(x) =\frac{x^{2} -6x-7x+42}{x^{2} -5x-5x+25}

R(x) =\frac{x^{2} -13x+42}{x^{2} -10x+25}

Hence, the simplified form of R(x) is R(x) =\frac{x^{2} -13x+42}{x^{2} -10x+25}

Learn more on Simplifying an expression here: brainly.com/question/1280754

#SPJ1

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The vertex of the parabola below is at the point (1.-3). Which of the equations below could be the one for this parabola?
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Answer: Choice D. y = (x-1)^2 - 3

The vertex is (h,k) = (1,-3). So h = 1 and k = -3.

We have a = 1 as the leading coefficient.

Plug those values into the equation below

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Step-by-step explanation:

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