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Kamila [148]
3 years ago
15

Number 2 says Write the given equation in exponential form. Log8 1/512=-3

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
7 0

In exponential form it is given as, 8⁻³ = $\frac{1}{512}

<u>Step-by-step explanation:</u>

We have to write the given equation in the exponential form, that is in the form of base to the power value.

Given:

log₈ ($\frac{1}{512} ) = -3

Here the base is 8.

In the exponential form, it is written as,

base to the power 3 = 512

Here the reciprocal of 512 is given, so,

base to the power -3 =   $\frac{1}{512}

So the exponential form is given as, 8⁻³ = $\frac{1}{512}

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What would the length be?
Natalka [10]

Answer:

EF = ~3.8

Step-by-step explanation:

Apply the sine theorem:

EF/sinD = DE/sinF

=> EF = DE*(sinD/sinF)

         = 3*(sin75/sin50)

         =3.78 = ~3.8

Hope this helps!

4 0
4 years ago
Please help! ^^' I'll give brainliest to the correct answer!
natita [175]
2, because ab=ac and they both equal 6 when plugged in
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3 years ago
Find the product of (x + 5)(x − 5) and show work
AleksandrR [38]

(x + 5) * (x − 5) =

x² - 25

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x * x = x² and 5 * (-5) = -25

8 0
3 years ago
Read 2 more answers
G is the incenter, or point of concurrency, of the angle bisectors of ΔACE.
vova2212 [387]

Answer:

▢ $\overline{DG}$ ≅ $\overline{FG}$

▢ $\overline{DG}$ ≅ $\overline{BG}$

▢ $\overline{GE}$ bisects \displaystyle ∠DEF

▢ $\overline{GA}$ bisects \displaystyle ∠BAF

Step-by-step explanation:

As you can see, angles \displaystyle BAF and \displaystyle DEF form two half-kites, which you should know have <em>two</em><em> </em><em>pairs of</em><em> </em><em>congruent</em><em> </em><em>sides</em>, therefore segments \displaystyle GA and \displaystyle GE are what you call angle bisectours, which is why segments \displaystyle FG, \displaystyle DG, and \displaystyle BG are congruent.

I am joyous to assist you at any time.

4 0
3 years ago
Can be used to compare changes from one period to another.
vlada-n [284]

Answer:

c) Percentages

Step-by-step explanation:

Percentages can be used to compare changes from one period to another.

In calculating a percentage change, either a percentage increase or percentage decrease, we must have both the new and old measurement of the specific quantity.

For example, let's find percentage increase of the number of students that joined a book club using the parameters below;

Original number of students = 32

New number of students = 36

We will calculate the increase using;

Increase = original \; number  -  new \; number

Substituting the values, we have;

Increase = 36 - 32 = 4

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Percentage \; increase = 0.125 * 100

Percentage increase = 12.5%

Therefore, the number of students in the school club increased by 12.5%.

8 0
3 years ago
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