Let 's x the length of the pyramid:
V=x²*h/3
V=1024 and h=12
So x²*12/3=1024
==>x²=1024*3/12
==>x²=256
==>x²=16²
==> x=16 for (x=-16 must be exclude <0)
......brainpower pts pls
4.8, I hope this helps you, I answered this earlier. :)
As we can see here any negative number subtracting another negative number leads to adding. So we would have -6+2 which would be -4. So therefore your answer is -4
Answer:
Step-by-step explanation:
The sine of an angle is equal to the y coordinate point where the terminal side of the angle intersects the unit circle.
<span>The name of the shape graphed by the function r ^ 2 = 9
cos (2 theta) is called the “<u>lemniscate</u>”. A lemniscate is a
plane curve with a feature shape which consists of two loops that meet at a
central point. The curve is also sometimes called as the lemniscate of
Bernoulli. </span>
Explanation:
The
period of coskθ is 2π/k. In this case, k = 2 therefore the
period is π.
r ^ 2 = 9 cos 2θ ≥0 → cos 2θ ≥0. So easily
one period can be chosen as θ ∈
[0, π] wherein cos 2θ ≥0.
As cos(2(−θ)) = cos2θ, the graph is symmetrical about the initial line.
Also,
as cos (2(pi-theta) = cos 2theta, the graph is symmetrical about the
vertical θ = π/2
A
Table for half period [0,π4/] is
adequate for the shape in Quarter1
Use symmetry for the other three quarters:
(r, θ) : (0,3)(3/√√2,π/8)(3√2/2,π/6)(0,π/4<span>)</span>
