Answer:
-15
Step-by-step explanation:
The negative is outside of the absolute value signs/lines. The absolute value is how far the number is from 0. So, it doesn't matter whether or not there is a negative sign inside of the absolute value lines it will always be positive. But, if it's outside of it, then it will be negative.
Lets calculate gear ration T2/T1
so the gear ratio will be 1.6 it simply means dat if u rotate large gears one full revolution it tends to turn another short wheel to 1.6 revs, so in ur qtion the large whell revs 100 den u must multiply wid 1.6*100= 160 revs
Answer: A: 3x^2y^(3/2)
Step-by-step explanation:
This can be written as
(81*x^8*y^6)^(1/4)
Then multiply each exponent by (1/4):
81^(1/4)*x^(8(1/4))y^6(1/4))
81^(1/4) = 3
x^(8(1/4)) = x^2
y^6(1/4)) = y^(3/2)
The result: 3x^2y^(3/2)
Answer:
Using the formula:
![A=P+I](https://tex.z-dn.net/?f=A%3DP%2BI)
where
A is the total amount
P is the principal
I is the Simple Interest
As per the statement:
Principal(P) = 5300 rupees.
rate of interest(r) = 6.5% = 0.065
Total amount(A) = 6678 rupees.
Then using above formula we have;
![6678 = 5300+I](https://tex.z-dn.net/?f=6678%20%3D%205300%2BI)
Subtract 5300 both sides we get;
![1378 = I](https://tex.z-dn.net/?f=1378%20%3D%20I)
or
![I = \$1378](https://tex.z-dn.net/?f=I%20%3D%20%5C%241378)
We have to find the time period.
Using formula of Simple interest:
![I = Prt](https://tex.z-dn.net/?f=I%20%3D%20Prt)
where r is the rate of interest (in decimal)
here, r = 6.5% = 0.065
Substitute the given values top find t:
![1378 = 5300 \cdot 0.065 \cdot t](https://tex.z-dn.net/?f=1378%20%3D%205300%20%5Ccdot%200.065%20%5Ccdot%20t)
⇒![1378 = 344.5t](https://tex.z-dn.net/?f=1378%20%3D%20344.5t)
Divide both sides by 344.5 we have;
![4 = t](https://tex.z-dn.net/?f=4%20%20%3D%20t)
Therefore, the time period t in years is 4 years