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3 years ago

This graph shows how fast a race car can travel in a stock car race

Mathematics

1 answer:

Nookie1986 [14]3 years ago

7 0

Answer:

C. In 2 seconds, the race car travels 180 meters.

Step-by-step explanation:

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Find the value of x in the equation below. 3x = 18

Oxana [17]

Answer:

x=6

Step-by-step explanation:

you need to get x alone so you divide by 3 on both sides

hope this helps!!! :)

example:

3x/3= 18/3

x=6

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3 years ago

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If one cup is equal to 8 fluid ounces, how many fluid ounces are in 4 cups? Input only whole numbers.

Levart [38]

4 cups = 32 oz. (:

I hope this helps. (:

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3 years ago

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Can someone please answer me this question ASAP!!!!

natulia [17]

3/6 because absolute value of any number has to be positive and you have to subtract the 2 answers to find the distance

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3 years ago

— 7х + Зу = 2<br> Which ordered pair is a solution of the equation

lidiya [134]

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3 years ago

Air pressure may be represented as a function of height (in meters) above the

denis-greek [22]

Answer: OPTION C.

Step-by-step explanation:

<h3> The complete exercise is: "Air pressure may be represented as a function of height (in meters) above the surface of the Earth, as shown below:</h3><h3> $P(h) =P_0e^{-0.00012h}$ </h3><h3> In this function $P_o$ is the air pressure at the surface of the earth, and $h$ is the height above the surface of the Earth, measured in meters. At what height will the air pressure equal 50% of the air pressure at the surface of the Earth"</h3><h3></h3>

Given the following function:

$P(h) =P_0e^{-0.00012h}$

In order to calculate at what height the air pressure will be equal 50% of the air pressure at the surface of the Earth, you can follow these steps:

1. You need to substitute $P(h)=0.5P_o$ into the function:

$0.5P_o=P_0e^{-0.00012h}$

2. Finally, you must solve for $h$ .

Remember the following property of logarithms:

$ln(b)^a=a*ln(b)\\\\ln(e)=1$

Then, you get this result:

$0.5P_o=\frac{P_o}{e^{0.00012h}}\\\\(0.5P_o)(e^{0.00012h})=P_o\\\\e^{0.00012h}=\frac{P_o}{0.5P_o}\\\\ln(e)^{0.00012h}=ln(2)\\\\0.00012h*1=ln(2)\\\\h=\frac{ln(2)}{0.00012}\\\\h=5576.2$

7 0

4 years ago