The question is telling you that the length of the rectangle is 3 metres more than twice the width.
So let:
<em>w= width</em>
<em>L= length</em>
Because the length is 3 metres more than twice<em> </em>the width: <em>L= </em><em>2</em><em>w+</em><em>3</em>
They also tell you the perimeter is 48 metres.
<em>P= L+L+w+w</em>
So the equation of the perimeter is:
<em>48= (2w+3)+(2w+3)+2w +2w</em>
<em>48= 2(2w+3) + 4w</em>
To find w, expand and simplify.
<em>48= 4w+6+4w</em>
<em>48= 8w + 6</em>
<em>42= 8w</em>
<em>5.25=w</em>
Now that you know the width, plug in the value into the length equation:
<em>L= 2w+3</em>
<em>L=2(5.25)+3</em>
<em>L=10.50+3</em>
<em>L=13.5</em>
If I am wrong let me know! I hope this helps.
[tex]Domain:x\geq0\\\\\sqrt{x}\leq5\ \ \ \ |square\ both\ sides\\\\x\leq25[tex]
Answer: B. 0 ≤ x ≤ 25
I hope this helps you
18=3^2.2
18=2.9
18=6.3
The complete factorisation of 50a²b⁵ − 35a⁴b³ + 5a³b⁴ is 5a²b³(10b² - 7a² + ab)
<h3>How to factorise?</h3>
Factorisation is the process of writing an expression as a product of two or more common factors.
The expression is written as a product of several factor.
Therefore,
50a²b⁵ − 35a⁴b³ + 5a³b⁴
Hence, the complete factorisation is as follows;
5a²b³(10b² - 7a² + ab)
learn more on factorisation here: brainly.com/question/2272501
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