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igor_vitrenko [27]
4 years ago
10

Standard form of 5.93e-5

Mathematics
2 answers:
Vanyuwa [196]4 years ago
7 0

Answer:

In standard form  0.0000593 .

Step-by-step explanation:

Given :5.93e^{-5}.

To find  : Standard form.

Solution : We have given that 5.93e^{-5}.

5.93* 10^{-5}  although the e notation is also valid.

We can write it in fraction form \frac{5.93}{10^{5} }.

Then ,  \frac{5.93}{100000}.

Remove decimal from numerator

\frac{593}{10000000}.

In standard form  

0.0000593

Therefore, In standard form  0.0000593 .

CaHeK987 [17]4 years ago
6 0

The correct answer is 0.0000593


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Problem B
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Answer:

The years are:

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Explanation:

<u>1. Years BC:</u>

a) Years with four digits:

The first number with 3 equal digits is 1000. After that the years go decreasing: 999, 998, 997, ...

b) Years with three digits:

From 999 to 111, the numbers have three digits, thus the only that are solutions ara 999, 888, 777, 666, 555, 444, 333, 222, and 111: 9 numbers

After that the years have two digits, thus no solutions, with two digits.

Hence, we count 10 different years.

<u>2. Years CE</u>

a) Years with three digits:

  • 111, 222, 333, 444, 555, 666, 777, 888, 999: 9 years

b) Years with four digits

i) Starting with 1:

  • With three 0: 1000: 1 year
  • With three 1: 1011, 1101, 1110: 3 years
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ii) Starting with 2:

  • With three 0: 2000: 1 year

The next one with three equal digits is 2111 and it is after 2020 CE.

Therefore, 9 + 1 + 3 + 8 + 1 = 22 years starting with 2.

<u>3. Total</u>

<u />

10 years BC and 22 years CE have exactly three digits the same: 10 + 22 = 32.

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