Answer:
3y5 • (5y + 7)2 • (5y - 7) then solve that which is (3•2y5) • (5y + 7) • (5y - 7) and keep going { 3x−2y=5 & 2x−5y=7
SOLVE FOR X, Y
x=1
y=−1
I hope this helps a little
Answer:
12-21+5=-4
Step-by-step explanation:
12-21=-9
-9+5=-4
1.A.
The base lengths of the trapezoid are 35cm and 19cm. The height is 15cm.
1.B.
The formula for the area of a trapezoid is
A=(b1+b2)/2*h
plug in the data we know
A=(35+19)/2*15
A=54/2*15
A=27*15
A=405cm²
since there are two trapezoids, we double that number 405*2=810cm²
Answer=810cm²
1.C.
To solve for this, we need to find the perimeter of the trapezoid
P=35+19+17+17=88cm
Answer=No. The edges of the trapezoid are longer than 80cm.
2.A.
3units. Since their x values are the same, you just subtract the y values to calculate distance 5-2=3
Answer=3
2.B
A right triangle. Since one coordinate is directly above, and the other is directly to the right of the bench
3.A
The two triangles would be...
A=1/2b*h=1/2*30*72=15*72=1080ft² each
and the center rectangle would be
A=l*w=20*72=1440ft²
Add them all together and you get
Total area=3600ft²
Answer:
10/3
Step-by-step explanation:
