Answer:
20sets
Step-by-step explanation:
Since we are to select 3 unordered letters from the word q, u, a, k, e, s, we will apply the combination rule.
For example if r objects are to be selected from n pool of objects, this can be done in nCr number of ways.
nCr = n!/(n-r)!r!
Since the total number of letter in the word q, u, a, k, e, s is 6letters and we are to form 3 letters from it unordered, this can be done in 6C3 number of ways.
6C3 = 6!/(6-3)!3!
6C3 = 6!/3!3!
6C3 = 6×5×4×3×2×1/3×2×1×3×2×1
6C3 = 6×5×4/3×2
6C3 = 120/6
6C3 = 20
Hence 20sets of selection are possible
