The function of the object height is an illustration of a projectile motion
The object will never hit the ground
<h3>How to determine when the object hits the ground?</h3>
The function is given as:
h=16t^2+80t+96.
When the object hits the ground, h = 0
So, we have:
16t^2+80t+96 = 0
Divide through by 16
t^2+5t+6 = 0
Expand
t^2 + 3t + 2t + 6 = 0
Factorize
t(t + 3) + 2(t + 3) = 0
Factor out t + 3
(t + 2)(t + 3) = 0
Solve for t
t = -2 or t = -3
The time (t) cannot be negative.
Hence, the object will never hit the ground
Read more about projectile motion at:
brainly.com/question/1130127
Answer: 1,278
Step-by-step explanation: 2(18x18)+2 1/2(18x14)
p.e.m.d.a.s. 18x18= 324 18x14= 252
2x324= 648 2.5x252=630
648+630 =1,278
Answer: Yes
Step-by-step explanation:
x>=8-3
x>=5
