Question

The table of values represents a function ​f(x).

Answer 1

Answer:

6490

Step-by-step explanation:

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Answer 2

Answer:

- The interval  [9, 10] is 1,375% greater than the interval [5, 8].

- The interval  [9, 10] is 14.75 times greater than the interval [5, 8].

Step-by-step explanation:

1. To solve this problem you must apply the following formula:

$AverageRateOfChange=\frac{y_{2}-y_{1}}{x_{2}-y_{1}}$

2. Let's calculate the average rate of change of each interval:

a) Interval [9,10]:

 $=\frac{11,014-4,052}{10-9}=6,962$

b) Interval [5,8]:

 $=\frac{1,491-75}{8-5}=472$

3. The difference is:

$6,962-472=6,490$

4. In percentage:

$(\frac{6,962-472}{472})(100)=1,375%$

5. You have that the interval [9,10] is 14.75 times greater than the interval [5,8], as you can see below:

$\frac{6,962}{472}=14.75$