All categories

3 years ago

What is the interquartile range (IQR) of the data set represented by this box

Mathematics

1 answer:

aleksandrvk [35]3 years ago

7 0

Answer:

5jsjbwbsbsbshgdhshe8wueieiieueuueueujejrjjrjfd

You might be interested in

35% of 20 is what number

EleoNora [17]

It's 7

Hope I helped! ( Smiles )

8 0

3 years ago

Read 2 more answers

How many zeros does the function ????(x) = 3x^2 + 6x + 2 have? Explain how you know.

maxonik [38]

Answer:

The function has 2 zeros:

$x = -1 - \frac{1}{\sqrt{3}}\\x = -1 + \frac{1}{\sqrt{3}}$

Step-by-step explanation:

When you have a polynomial function, you can identify the grade of the function (the grade is the maximum potency) and this is the number of zeros that the function will have. In this case, you have a second-grade polynomial function that has 2 zeros.

6 0

3 years ago

In which quadrant of the coordinate graph does point F lie?

cupoosta [38]

4 buddy now don’t forget that Brainly answer

5 0

3 years ago

Read 2 more answers

If thewronskian w of f and g is 3e4t,and if f(t) = e2t,find g(t).

ehidna [41]

$W(f(x),g(x))=\begin{vmatrix}f(x)&g(x)\\f'(x)&g'(x)\end{vmatrix}=f(x)g'(x)-g(x)f'(x)$

We have $f(t)=e^{2t}\implies f'(t)=2e^{2t}$ , so

$W(f(t),g(t))=e^{2t}g'(t)-2e^{2t}g(t)=3e^{4t}$
$\implies e^{-2t}g'(t)-2e^{-2t}g(t)=3$
$\implies\dfrac{\mathrm d}{\mathrm dt}[e^{-2t}g(t)]=3$
$\implies e^{-2t}g(t)=\displaystyle\int3\,\mathrm dt$
$\implies e^{-2t}g(t)=3t+C$
$\implies g(t)=3te^{2t}+Ce^{2t}$

where $C$ is any arbitrary constant.

8 0

4 years ago

To teach computer programming to employees, many firms use on the job training. A human resources administrator wishes to review

tatiyna

Answer:

The z-score for the trainee is of 2.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The mean of the test scores is 72 with a standard deviation of 5.

This means that $\mu = 72, \sigma = 5$

Find the z-score for a trainee, given a score of 82.

This is Z when X = 82. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{82 - 72}{5}$

$Z = 2$

The z-score for the trainee is of 2.

3 0

3 years ago