The histogram is especially useful in comparing mean and median values of a variable. We have that 5.5+6+7+10+7.5+8+9.5+9+8.5+8+7+7.5+6+6.5+5.5=111.5 Since there are 15 values, their mean is 111.5/15=7.43 which is very close to the mean. We also have that 7 onservations are lower than 7.4 while 8 are bigger than 7.4; hence, the diagram is rather balanced and not left-skewed. We cannot tell immediately which one is larger since the values are too close. Any such random process can usually be approximated to a greater or smaller degree by a normal curve; the more points, the better. The histogram shows this (it is kind of a discrete normal curve); all points except 4 will be in this interval of bars.
Answer:
C, D, B
Step-by-step explanation:
the mode is if a number is repeated more than one time
EX. 15, 23, 15, 23, 15
C because 15 is repeated 3 times and 19 is too.
D because 42 is repeated 2 times and so is 18.
B because 87 is repeated 2 times and 32 is too.
Answer:
x=-2
y= 8
Step-by-step explanation:
Given data
10x – 2y = -36-----------1
7x – 2y = -30--------------2
-Subtract to eliminate y
3x-0= -6
3x= -6
x= -6/3
x= -2
Put x= -2 in
7(-2)– 2y = -30
-14-2y=-30
-14+30=2y
16=2y
y= 16/2
y= 8
The solution is <span>B. π/12+nπ
</span>proof
sinx cosx = 1/4 is equivalent to 2 <span>sinx cosx = 1/2 or sin2x =1/2
so 2x = arcsin(1/2) = </span>π/6 + 2nπ, so x = π/12+nπ
