Answer:
Option A) any numerical value in an interval or collection of intervals
Step-by-step explanation:
Continuous Random Variable:
- A continuous random variable can take any value within an interval.
- Thus, it can take infinite values since there are infinite numbers in an interval.
- A continuous variable is a variable whose value is obtained by measuring.
- Examples: height of students in class
, weight of students in class, time it takes to get to school, distance traveled between classes.
- Thus, the correct meaning of continuous random variable is explained by Option A)
Option A) any numerical value in an interval or collection of intervals
The answer to this question is 2 because 3-3=0×6=0+2=2
Answer:
5 people
Step-by-step explanation:
For each people Ms Hernandez bring to the zoo, she will pay $15.50, so if she go alone, 1×15.50, if she go with one person, 2×15.50, with three 3×15.50, and keep growing this way. The price each person pay is constant and equal to 15.50, and what will determine the final price is the number of people. Also remember that she always will have to pay $ 10 on parking, so you can write an equation with this:
15.50x +10 = y, as x being the number of people and y being the final price.
She have $100, so this is the max she can spend. Two know the number of people she can bring to the zoo, put 100 in place of y and find the value of x:
15.50x + 10 = 100
15.50x = 100 - 10
15.50x = 90
x = 90/15.50
x = 5.8
But there's no way to bring 0.8 person, so the max she can bring are 5 people, including her
If f(x) has an inverse on [a, b], then integrating by parts (take u = f(x) and dv = dx), we can show
Let 
. Compute the inverse:
![f\left(f^{-1}(x)\right) = \sqrt{1 + f^{-1}(x)^3} = x \implies f^{-1}(x) = \sqrt[3]{x^2-1}](https://tex.z-dn.net/?f=f%5Cleft%28f%5E%7B-1%7D%28x%29%5Cright%29%20%3D%20%5Csqrt%7B1%20%2B%20f%5E%7B-1%7D%28x%29%5E3%7D%20%3D%20x%20%5Cimplies%20f%5E%7B-1%7D%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%5E2-1%7D)
and we immediately notice that ![f^{-1}(x+1)=\sqrt[3]{x^2+2x}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%2B1%29%3D%5Csqrt%5B3%5D%7Bx%5E2%2B2x%7D)
.
So, we can write the given integral as
Splitting up terms and replacing 
in the first integral, we get
