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3 years ago

Can someone help me pls

Mathematics

1 answer:

Artist 52 [7]3 years ago

3 0

Answer:

PΔJKL=66

Step-by-step explanation:

so we are given the line segments JK, KL, and LJ which are tangent to k(O), and also that JA=9, AL=10, and CK=14

JL=JA+AL (parts whole postulate)

JL=9+10=19 (substitution, algebra)

JA=JB=9 (tangent segments from the same point are congruent)

CK=KB=14 (tangent segments from the same point are congruent)

JK=JB+KB (parts whole postulate)

JK=9+14=23 (substitution, algebra)

LA=LC=10 (tangent segments from the same point are congruent)

LK=LC+CK (parts whole postulate)

LK=10+14=24 (substitution, algebra)

Perimeter of ΔJKL=LK+KL+LJ (perimeter formula for triangles)

Perimeter of ΔJKL=23+24+19=66 (substitution, algebra)

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